Question

'arr'数组是根据用户输入动态创建的，因此其内容会在功能版本中发生变化。用户输入可以是任何长度，因此可能不一定包含5个单词。问题是我不确定如何使用不同数量的子项动态创建words对象，以便将其推送到combos的正确成员。

var arr = [
  [
    ["this", 0],
    ["is", 1],
    ["a", 2],
    ["complete", 3],
    ["sentence", 4],
    ["with", 5],
    ["index", 6],
    ["data", 7]
  ]
];

var partOne = {
  two: [],
  three: [],
  four: [],
  five: []
}

var len = arr.length;

var print = [];

for (var i = 0; i < len; i++) {
  var lenGr = arr[i].length;
  for (var j = 0; j < lenGr - 1; j++) {
    partOne.two.push({
      "words": {
        "word1": arr[i][j],
        "word2": arr[i][j + 1]
      }
    });
  }
  for (j = 0; j < lenGr - 2; j++) {
    partOne.three.push({
      "words": {
        "word1": arr[i][j],
        "word2": arr[i][j + 1],
        "word3": arr[i][j + 2]
      }
    });
  }
  for (j = 0; j < lenGr - 3; j++) {
    partOne.four.push({
      "words": {
        "word1": arr[i][j],
        "word2": arr[i][j + 1],
        "word3": arr[i][j + 2],
        "word4": arr[i][j + 3]
      }
    });
  }
  for (j = 0; j < lenGr - 4; j++) {
    partOne.five.push({
      "words": {
        "word1": arr[i][j],
        "word2": arr[i][j + 1],
        "word3": arr[i][j + 2],
        "word4": arr[i][j + 3],
        "word5": arr[i][j + 4]
      }
    });
  }
}

console.log("Current solution : ");
console.log(partOne);

var partTwo = {
  two: [],
  three: [],
  four: [],
  five: []
};
for (i = 0; i < len; i++) {
  var lenGr = arr[i].length;
  $.each(partTwo, function(ind, val) {
    for (var j = 1; j < 4; j++) {
      for (var k = 0; k < lenGr - j; k++) {
        // Populate 'partTwo' dynamically, in the same format as partOne.
      }
    }
  });
}

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Answer 1

我只提供了一个监视j的switch语句，以确定在该迭代期间计算的数组成员数，然后重复原始代码以将新对象推送到partTwo。可能有一个更优雅的解决方案。

＆＃13;

var arr = [
  [
    ["this", 0],
    ["is", 1],
    ["a", 2],
    ["complete", 3],
    ["sentence", 4],
    ["with", 5],
    ["index", 6],
    ["data", 7]
  ]
];

var partTwo = {
  two: [],
  three: [],
  four: [],
  five: []
};

var len = arr.length;

for (i = 0; i < len; i++) {
  var lenGr = arr[i].length;
  for (var j = 1; j < 5; j++) {
    for (var k = 0; k < lenGr - j; k++) {
      switch (j) {
        case 1:
          partTwo.two.push({
            "words": {
              "word1": arr[i][k],
              "word2": arr[i][k + 1]
            }
          });
          break;
        case 2:
          partTwo.three.push({
            "words": {
              "word1": arr[i][k],
              "word2": arr[i][k + 1],
              "word3": arr[i][k + 2]
            }
          });
          break;
        case 3:
          partTwo.four.push({
            "words": {
              "word1": arr[i][k],
              "word2": arr[i][k + 1],
              "word3": arr[i][k + 2],
              "word4": arr[i][k + 3]
            }
          });
          break;
        case 4:
          partTwo.five.push({
            "words": {
              "word1": arr[i][k],
              "word2": arr[i][k + 1],
              "word3": arr[i][k + 2],
              "word4": arr[i][k + 3],
              "word5": arr[i][k + 4]
            }
          });
          break;
        default:
          console.log("Error with j switch.");
      }
    }
  }
}
console.log(partTwo);

＆＃13;

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＆＃13;

JQuery：将不同长度的动态分配对象推送到对象

1 个答案: