Question

我需要在左边做一个div dissapear，然后从右边出现第二个。我正在使用以下jquery UI函数来执行此操作：

hide("slide", { direction: "left" }, 1000);
show("slide", { direction: "right" }, 1000);

我得到的问题是，当你在这个小提琴中看到时，第一个和第二个div在消失和进入时没有被分配：

https://jsfiddle.net/oagxfpru/

我想让第二个div在进入场景时处于同一高度。

有什么想法吗？感谢您的帮助＆lt; 3

Answer 1

$(document).ready(function() {
    $("#second").hide();
    
    $("#toSecond").on('click', function() {
        $("#first").hide("slide", { direction: "left" }, 1000);
        $("#second").show("slide", { direction: "right" }, 1000);
    });

    $("#toFirst").on('click', function() {
        $("#second").hide("slide", { direction: "left" }, 1000);
        $("#first").show("slide", { direction: "right" }, 1000);
    })
});

#first{float:left;
width:100%;}
#second{width:100%;}

<body>
    <div id='first'>
        Some content here<br/>
        that should slide to the left<br/>
        No problem with that
        <input type="button" id="toSecond" value="to second">
    </div>
    <div id='second'>
        This should be at the same height<br/>
        then the first div when sliding to the left<br/>
        This ain't working properly :/
        <input type="button" id="toFirst" value="to first">
    </div>

    <script src="https://code.jquery.com/jquery-3.2.1.min.js" integrity="sha256-hwg4gsxgFZhOsEEamdOYGBf13FyQuiTwlAQgxVSNgt4=" crossorigin="anonymous"></script>
    <script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js" integrity="sha256-T0Vest3yCU7pafRw9r+settMBX6JkKN06dqBnpQ8d30=" crossorigin="anonymous"></script>
    <script type="text/javascript" src="test.js"></script>
</html>

使用jquery ui进行水平滑动

1 个答案: