我需要显示每个类别的项目。我使用smarty模板。所以我得到这样的类别:
{foreach $news as $article}
<div class="panel panel-info">
<div class="panel-heading">{$article["name"]}</div>
<div class="panel-body">
"Here I need to display Items that have FOREIGN KEY 'category_id'"
</div>
</div>
{/foreach}
我是否应该获取类别的ID以及如何显示它? It's a category list with ID
我想改进我的问题 - 这里有一些指向我Controller的链接。我试图建立更多的链接,但我不能低声望。请试着看看我做错了什么?
答案 0 :(得分:0)
<?php
$lists = '';
$query = "your query example" - mysqli_query($conn,"select * from article");
if(!$mysqli_num_rows<0){
while($row = mysqli_fetch_array($query,MYSQLI_ASSOC)){
$id = $row["category_id"];
$name = $row["name"];
$lists .= '<div class="panel panel-info">
<div class="panel-heading">'.$name.'</div>
<div class="panel-body">
"Here I need to display Items that have FOREIGN KEY '.$id.'"
</div>
</div>';
}
echo $lists;
}
?>