$_SESSION['post'] = array($_SESSION['gender'],$_SESSION['star'],$_SESSION['caste'],$_SESSION['marital'],$_SESSION['salary'],$_SESSION['education'],$_SESSION['from'],$_SESSION['to'],$_SESSION['district'],$_SESSION['country_liv']);
$post=$_SESSION['post'];
echo $post[9]; //printing the country value
$page = (int)(!isset($_GET["page"]) ? 1 : $_GET["page"]);
if ($page <= 0) $page = 1;
$per_page = 5; // Set how many records do you want to display per page.
$startpoint = ($page * $per_page) - $per_page;
$statement = "`tbl_member` where member_id!=$member_id AND TIMESTAMPDIFF(YEAR, dob, CURDATE())>='$post[6]' AND
TIMESTAMPDIFF(YEAR, dob, CURDATE())<='$post[7]' AND gender Like '$post[0]%' AND star LIKE '%$post[1]%' AND caste LIKE '%$post[2]%' AND mari_status LIKE '%$post[3]%' AND education LIKE '%$post[5]%' AND city_town LIKE '$post[8]%' AND month_income LIKE '%$post[4]%' AND country_liv LIKE '%$post[9]%'";
$results=mysqli_set_charset($conDB, "utf8");
$results = mysqli_query($conDB,"SELECT * FROM {$statement} LIMIT {$startpoint} , {$per_page}");
现在我编辑了...... 我的所有编码都请帮助我....
我想在结果中显示特定国家....
我可以获得用户输入但是当我使用此查询时它无法正常工作.. 现在我编辑了...... 我的所有编码都请帮助我....
我想在结果中显示特定国家....
我可以获得用户输入但是当我使用此查询时它无法正常工作..
答案 0 :(得分:0)
I'M changed the statement this :
$statement = "`tbl_member` where member_id!=$member_id AND TIMESTAMPDIFF(YEAR, dob, CURDATE())>='$post[6]' AND
TIMESTAMPDIFF(YEAR, dob, CURDATE())<='$post[7]' AND gender Like '$post[0]%' AND star LIKE '%$post[1]%' AND caste LIKE '%$post[2]%' AND mari_status LIKE '%$post[3]%' AND education LIKE '%$post[5]%' AND city_town LIKE '$post[8]%' AND month_income LIKE '%$post[4]%' AND country_liv LIKE '%$post[9]%'";
到此:
$statement = "`tbl_member` where month_income LIKE '%$post[4]%' AND TIMESTAMPDIFF(YEAR, dob, CURDATE())>='$post[6]' AND
TIMESTAMPDIFF(YEAR, dob, CURDATE())<='$post[7]' AND member_id!=$member_id AND country_liv LIKE '%$post[9]%' AND gender Like '$post[0]%' AND star LIKE '%$post[1]%' AND caste LIKE '%$post[2]%' AND mari_status LIKE '%$post[3]%' AND education LIKE '%$post[5]%' AND city_town LIKE '$post[8]%' ";
谢谢各位朋友......为我工作