Question

 File customer = new File("Cus.txt");
    Scanner readCustomer = new Scanner(customer);
    while(readCustomer.hasNextLine())
    {
        String line = readCustomer.nextLine();
        String delims = ", ";
        String[] split = line.split(delims);
        int arr = Integer.parseInt(split[0]);
        int ser = Integer.parseInt(split[1]);
        int qui = Integer.parseInt(split[2]);
        int appt = Integer.parseInt(split[3]);
        int appL = Integer.parseInt(split[4]);
        Customer newCustomer = new Customer(arr, ser, qui, appt, appL);
        customerList.add(newCustomer);
        System.out.println("Customer arrival: " + newCustomer);
    }readCustomer.close();

输出

912, 4, 922, 0, 0
915, 5, -1, 10, 10
918, 0, -1, 5, 5
920, 0, -1, 10, 10
925, 6, 930, 0, 0

CUS.TXT文件

915, 5, -1, 925, 10,  
918, 0, -1, 920, 5, 
920, 0, -1, 915, 10,  
925, 6, 930, -1, 0,

我真的很茫然，不知道如何解决这个问题。有没有人看到任何错误或为什么它在我的分裂中无法读取[4]？为什么要复制int appt值中的内容？

Answer 1

@ Jamie我无法理解你是如何获得输出的，因为你打印的是对象而不是值。我在你的代码中没有改变任何东西，它对我来说很好。你可能错过了很小的东西。使用以下代码，您将能够获得所需的输出。

import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;

public class ReadingInputIncorrectly {
    public static void main(String[] args) throws FileNotFoundException {
        ArrayList<Customer> customerList=new ArrayList<>();
        File customer = new File("path to your Cus.txt file");
        Scanner readCustomer = new Scanner(customer);
        while (readCustomer.hasNextLine()) {
            String line = readCustomer.nextLine();
            String delims = ", ";
            String[] split = line.split(delims);
            int arr = Integer.parseInt(split[0]);
            int ser = Integer.parseInt(split[1]);
            int qui = Integer.parseInt(split[2]);
            int appt = Integer.parseInt(split[3]);
            int appL = Integer.parseInt(split[4]);
            Customer newCustomer = new Customer(arr, ser, qui, appt, appL);
            customerList.add(newCustomer);
            System.out.println(newCustomer.num1+", "+newCustomer.num2+", "+newCustomer.num3+", "+newCustomer.num4+", "+newCustomer.num5+", ");
        }
        readCustomer.close();
    }
}
class Customer{
    int num1,num2,num3,num4,num5;
    Customer(int num1,int num2,int num3,int num4,int num5){
        this.num1=num1;
        this.num2=num2;
        this.num3=num3;
        this.num4=num4;
        this.num5=num5;
    }
}

<强>输出

915, 5, -1, 925, 10, 
918, 0, -1, 920, 5, 
920, 0, -1, 915, 10, 
925, 6, 930, -1, 0,

Cus.txt文件

915, 5, -1, 925, 10,  
918, 0, -1, 920, 5, 
920, 0, -1, 915, 10,  
925, 6, 930, -1, 0,

让我知道它是否有效。

扫描仪无法正确读取输入

1 个答案: