Question

 from random import random

 def computer():
 computer = 0
 while computer < 21:
  val = int(random()*10)+1
  if (computer + val) > 21:
   break
  else:
   computer += val
 print "Ich habe ", computer, "!"
 return computer


    def player():
 player = 0
 loss = 0
 while player < 21:
                hval = int(random()*10)+1
                print "Du hast ", hval, "...\nNoch eine mit y..."
                if raw_input == "y":
                        player += hval
                        if player > 21:
                                print "Du hast verloren!"
                                loss = 1
                                break
                        else:
                                continue
                else:
                        player += hval
                        break
        return player
        return loss

    if __name__ == "__main__":
        player()
        if loss == 1: #This is where I get the NameError.
                pass
        else:
                computer()
                if computer > player:
                        print "Ich habe gewonnen!"
                else:
                        print "Du hast gewonnen"

我在播放器（）中返回了丢失，所以我不知道为什么我一直得到这个NameError。

Answer 1

让我们清理那些混乱，看看所有错误是什么：

from random import random # tip, check out randint (the function in the random module)

def computer():
    computer = 0
    while computer < 21:
        val = int(random()*10)+1 # please use some whitespace around operators

        if (computer + val) > 21:
            break

        else:
            computer += val

    print "Ich habe ", computer, "!"
    return computer

def player():
    player = 0
    loss = 0

    while player < 21:
        hval = int(random()*10)+1 # again, whitespace improves readability
        print "Du hast ", hval, "...\nNoch eine mit y..."

        if raw_input == "y": # raw_input is a function (hint you need to call the function)
                             # you're comparing the object against a string
                             # that will always yield false, therefore the player
                             # never gets the chance to enter another number

            # this never gets executed
            player += hval
            if player > 21:
                print "Du hast verloren!"
                loss = 1
                break

            else:
                continue

        # always gets executed
        else:
            player += hval
            break

    return player # this returns the value of player
    return loss # never reached, dead code, the return above has already left the function

if __name__ == "__main__":
    player() # returns the integer, but doesn't assign it to any name

    if loss == 1: # loss is not defined in this scope
        pass

    else:
        computer() # again, this doesn't assign the returned value

    if computer > player: # if this would get reached, it would fail yet again
                          # no name error this time, but you're comparing the function object
                          # against the player object, this will (at least in CPython)
                          # compare the memory addresses

        print "Ich habe gewonnen!"

    else:
        print "Du hast gewonnen"

现在您知道所有错误，由您来解决它们：）

但我还要注意，你的缩进是一个 REAL 混乱，每个缩进从1个空间到16个。
特别是在Python中，缩进是语法的一个重要部分，这绝不是可以容忍的。

请阅读PEP8有关如何设置代码样式的信息。

Answer 2

当你写return loss时，它会返回损失的值，而不是变量。因此，调用范围中不存在名称loss。

您需要将结果分配给局部变量（也称为丢失），如下所示：

loss = player()

Answer 3

在你的脚本中没有定义丢失，发布整个脚本以便我们可以跟进它，可能是你试图引用你在player中使用的变量（）

Answer 4

您应该修改格式，但除此之外，如果您从loss返回player()，则不会将其保存在任何位置。

if __name__ == "__main__":
    loss = player()   # the loss returned by player is now within the local loss
    if loss == 1: #This is where I get the NameError.
            pass

Python：NameError没有明显的原因？

4 个答案: