我希望在显示之前从我的数组中删除多个特定元素。这是我的代码,但它没有显示任何元素:
$('[data-fancybox]').on('click', function() {
var visibleLinks = $('.fancybox:visible');
$.fancybox.open( visibleLinks, {
//options go here
caption: function (instance, item) {
var caption, link, collectTags, tags, filterTags, filteredTags;
function format(tpl, binding) {
if (typeof binding != 'function') return format(tpl, function (_, name) {
return binding[name];
});
return tpl.replace(/\$(\w+)/g, binding);
}
caption = $(this).data('caption');
link = format('<br>See more pictures', item);
collectTags = $(this).parent().attr("class").split(' ');
function createTag(it) {
return format("<a href='$site$it'>$it</a>", {
site: (it == 'wedding' || it == 'concert') ? 'http://example.com/gallery/#filter=.' : 'http://example.com/gallery/#filter=.',
it: it
});
}
filterTags = ['churchevent', 'corporate'];
filteredTags = tags.filter(function(itm){return itm!== filterTags});
tags = $.map(collectTags, createTag);
return [].concat(caption ? [caption, link] : link).concat(filteredTags.slice(1).join(', ')).join('<br>');
}
}, visibleLinks.index( this ) );
return false;
});
答案 0 :(得分:1)
我想,因为你写了&#34;删除多个特定元素&#34;你想删除filterTags。
如果是这样的话,那就改变一下:
filterTags = ['churchevent', 'corporate'];
filteredTags = tags.filter(function(itm){return itm!== filterTags});
tags = $.map(collectTags, createTag);
return [].concat(caption ? [caption, link] : link).concat(filteredTags.slice(1).join(', ')).join('<br>');
到此:
filterTags = ['churchevent', 'corporate'];
tags = $.map(collectTags, createTag);
filteredTags = tags.filter((item)=>{
for(tag in filterTags) if (item.indexOf(filterTags[tag]) != -1) return false;
return true;
});
return [].concat(caption ? [caption, link] : link).concat(filteredTags.slice(1).join(', ')).join('<br>');
否则只需在过滤方法中使用!= -1而不是== -1。
答案 1 :(得分:0)
什么是&#34;标签&#34;在tags.filter
的背景下?我假设它是一些数组。在任何一种情况下,您的过滤器都会检查标记中的项目是否等于filterTags
数组。当然,数组中的单个项目不等于数组,因此这将始终返回true,因此不会过滤任何内容。
我想你可能想要这样的东西:
filteredTags = tags.filter(function(itm){return filterTags.indexOf(itm) !== -1});
答案 2 :(得分:0)
你是在谈论这个阵列吗?
filterTags = ['churchevent', 'corporate'];
filteredTags = tags.filter(function(itm){return itm!== filterTags});
// Of note, you are creating tags just below this code. Should you move it up?
// Or rename tags => collectionTags???
// Either way, the filter function you are using is not doing what you expect.
tags.filter(function(itm){
// itm will be whatever, I'm guessing a string of some sort like "churchevent"
// Now you are trying to compare a string like "churchevent" to the
// array filterTags.
// This is what is happening...
return itm !== ['churchevent', 'corporate'];
// What you want to do is this in ES5
return (filterTags.indexOf(itm) === -1);
// or this in ES6
return !filterTags.includes(itm);
// Note the bang in front.
// TRUE will put itm in the tags array, FALSE will not.
}
另外,请参考MDN中的过滤功能。