SQL 2012使用Joins连接多个表中的多个查询并计入单个表

时间:2017-04-05 20:55:55

标签: sql sql-server count union

我有一种情况我不确定是否有可能这样做。
我有两个表需要加入并使用计数。

表1 =“EPM_ProjectUserview”

[ProjectUID], [ProjectName], [EnterpriseProjectTypeUID](used as a filter)

Table2 =“EpmTask_UserView”

[ProjectUID],[Task_Significance], [TaskPercentCompleted] then 3 count fields 
[total Count], [Count 100% complete], Count <1005]

这会给我一张看起来像这样的表 注意:第一列不适合项目名称

|Apps|Overall% Comp| Totl Count|100% Compl|Not 100% Comp|Overall Health|

接口的同一行是真的

总体完成百分比和总体健康状况来自摘要任务
   (这是项目服务器)
ProjectUID是连接的关键字段。

所以我有5个不同的查询都可以工作但是,当然我需要它们在1个表中。

查询1 - 这是项目名称projectUID和EnterpriseprojecttypeUID

SELECT [ProjectName]
   ,[ProjectUID]
   ,[EnterpriseProjectTypeUID]
  FROM [dbo].[MSP_EpmProject_UserView]
 where [projectUID] not like '0000CF75-FB12-4FFC-A404-AEC4F3258A9C'
 And
 [EnterpriseProjectTypeUID] like '76194144-3CDB-E611-9419-00215A9259E8'
 order by  [ProjectName] 

查询2这给出了每种类型的总数

SELECT p.[ProjectName]
  ,T.[Task_Significance]
 -- ,T.[TaskPercentCompleted]
  ,count (*) as [Total Count]
  FROM [psmado].[dbo].[MSP_EpmProject_UserView] as P
  join   [PSMADO].[dbo].[MSP_EpmTask_UserView] as T
  On T.[projectUID] = P.[projectUID]
  where 
  ([Task_Significance] like 'App'
   Or
   [Task_Significance] like 'Interface')
   Group by [ProjectName], [Task_Significance]

查询3-下一个查询为我提供了100%完整列

         SELECT p.[ProjectName]
  ,T.[Task_Significance]
 -- ,T.[TaskPercentCompleted]
  ,count (*) as [Count]
 FROM [psmado].[dbo].[MSP_EpmProject_UserView] as P
join   [PSMADO].[dbo].[MSP_EpmTask_UserView] as T
 On T.[projectUID] = P.[projectUID]
  where T.[TaskPercentCompleted] >= 100
  and
 ([Task_Significance] like 'App'
 Or
 [Task_Significance] like 'Interface')
   Group by [ProjectName], [Task_Significance]

查询4 - 下一个给出了不到100%完成的

SELECT p.[ProjectName]
  ,T.[Task_Significance]
 -- ,T.[TaskPercentCompleted]
  ,count (*) as [Count]
 FROM [psmado].[dbo].[MSP_EpmProject_UserView] as P
 join   [PSMADO].[dbo].[MSP_EpmTask_UserView] as T
 On T.[projectUID] = P.[projectUID]
 where T.[TaskPercentCompleted] < 100
 and
 ([Task_Significance] like 'App'
 Or
 [Task_Significance] like 'Interface')
 Group by [ProjectName], [Task_Significance]

查询5最后,整体任务运行状况和%完成来自表中的另一行

SELECT [dbo].[MSP_EpmProject_UserView].[ProjectName]
   ,[dbo].[MSP_EpmTask_UserView].[ProjectUID]
  ,[dbo].[MSP_EpmTask_UserView].[TaskName] as [Name]
  ,[dbo].[MSP_EpmTask_UserView].[TaskPercentCompleted] as [% Complete]
  ,[dbo].[MSP_EpmTask_UserView].[Task Health] as [Health]
  ,[dbo].[MSP_EpmTask_UserView].[Task_Significance]
  ,[dbo].[MSP_EpmTask_UserView].[TaskOutlineNumber]
  FROM [dbo].[MSP_EpmTask_UserView]
  inner join [PSMADO].[dbo].[MSP_EpmProject_UserView] 
  on [dbo].[MSP_EpmTask_UserView].[projectuid] = [PSMADO].[dbo].[MSP_EpmProject_UserView].[ProjectUID]
  where [dbo].[MSP_EpmTask_UserView].[projectUID] not like '0000CF75-FB12-4FFC-A404-AEC4F3258A9C' -- the timesheet project null
  and [Task_Significance]  like 'App Summary'
 or [Task_Significance]  like 'Interface Summary'
 order by  [ProjectName], [TaskOutlineNumber]

这些可以放在一张桌子上(工会对我不起作用)如果是这样的话怎么样?

感谢您的帮助

杰克的回答非常接近。这就是我需要的: enter image description here

这就是我所得到的。你可以看到它只是重复每个部分。 (我把它的一部分切掉了但是有36排。)

enter image description here

2 个答案:

答案 0 :(得分:2)

谢谢大家的意见和帮助。这是一个很棒的社区!所以我最终走向了另一个方向,因为杰克的想法让我走上了一条道路。

SELECT  pr.[ProjectName]
 ,T.[Task_Significance]

     , sum (case when T.[TaskPercentCompleted] is not null and T.[Task_Significance] ='App' Or T.[TaskPercentCompleted] is not null and T.[Task_Significance] = 'Interface'  then 1 else 0 end) as [Total]
 , sum (case when T.[TaskPercentCompleted] < 30 and T.[Task_Significance] ='App' Or T.[TaskPercentCompleted] < 30 and T.[Task_Significance] = 'Interface'  then 1 else 0 end) as [Incomplete]
 , sum (case when T.[TaskPercentCompleted] >= 30 and T.[Task_Significance] ='App' Or T.[TaskPercentCompleted] >= 30 and T.[Task_Significance] = 'Interface'  then 1 else 0 end) as [Complete]
   FROM [psmado].[dbo].[MSP_EpmProject_UserView] as Pr
 join   [PSMADO].[dbo].[MSP_EpmTask_UserView] as T
 On T.[projectUID] = Pr.[projectUID]
 Where
 T.[Task_Significance] like 'App'
 Or
 T.[Task_Significance] like 'Interface'

 Group by pr.[ProjectName], T.[Task_Significance]

答案 1 :(得分:1)

这里最好和最简单的方法是..使用公用表表达式.. 它不允许我将所有代码粘贴到此表达式中,但您可以使用以下语法直接执行此操作。

;将t1作为(在这些括号内粘贴您的第一个查询已满), t2 as(在这些括号内粘贴第二个查询完整), t3 as(在这些括号内粘贴你的第三个查询全部), t4 as(在这些括号中粘贴你的第四个查询全部), t5 as(在这些括号内粘贴你的第5个查询)

完成此操作后,编写查询并提取所需的任何数据。例如

从t1,t2,t3,t4,t5选择t1.abc,t2.abc,t3.xyz,t4.lmn,t5.xyz

希望这有帮助。