Question

我在Symfony 3.2.7控制器中有以下方法：

public function updateAction(Request $request)
{
    $em        = $this->getDoctrine()->getManager();
    // this is the original entity without modified values
    $entity    = $em->getRepository('QuoteBundle:Quote')->find($request->query->get('id'));

    // the entity passed to the form has the values modified coming from the request    
    $form = $this->createForm(CFProgramLevelQuoteType::class, $entity);
    ...
}

这就是形式：

class CFProgramLevelQuoteType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('CFProgramLevel', EntityType::class, [
                'class'         => 'QuoteBundle:CFProgramLevel',
                'choice_label'  => 'description',
                'placeholder'   => 'Please select a program',
            ]);
    }
    ...
}

我将使用查询生成器过滤QuoteBundle:CFProgramLevel中的某些值，因此我需要从$entity获取未修改的ID并将其发送到表单。这是我到目前为止所考虑的解决方案：

public function updateAction(Request $request)
{
    $em        = $this->getDoctrine()->getManager();
    $entity    = $em->getRepository('QuoteBundle:Quote')->find($request->query->get('id'));
    $entity_id = $entity->getCfProgramLevel()->getcfProgramLevelId();   
    $form = $this->createForm(CFProgramLevelQuoteType::class, $entity);
    ...
}

但是我如何将entity_id传递给表单并在那里使用它？如果有更好的方法来实现这一目标，我愿意听取意见。我在谷歌找不到任何有用的东西，所以任何帮助都表示赞赏。

更新

尝试下面答案中提供的解决方案我无法使其工作：

// controller
$form = $this->createForm(CFProgramLevelQuoteType::class, $entity, ['entity_id' => $entity_id]);

// form
public function buildForm(FormBuilderInterface $builder, array $options)
{
    dump($options);
    die();
    ...
}

public function setDefaultOptions(OptionsResolver $resolver)
{
    $resolver->setDefaults(['data_class' => Quote::class, 'entity_id' => null]);
    $resolver->setRequired('entity_id');
}

选项“entity_id”不存在。定义的选项是：“行动”， “allow_extra_fields”，“attr”，“auto_initialize”，“block_name”， “by_reference”，“compound”，“constraints”，“csrf_field_name”， “csrf_message”，“csrf_protection”，“csrf_token_id”， “csrf_token_manager”，“data”，“data_class”，“disabled”，“empty_data”， “error_bubbling”，“error_mapping”，“extra_fields_message”， “inherit_data”，“invalid_message”，“invalid_message_parameters”， “label”，“label_attr”，“label_format”，“mapped”，“method”， “post_max_size_message”，“property_path”，“required”， “translation_domain”，“trim”，“upload_max_size_message”， “validation_groups”。

Answer 1

您可以为表单类型创建自己的自定义选项，如http://symfony.com/doc/current/form/create_custom_field_type.html#defining-the-field-type

中所述

class CFProgramLevelQuoteType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        //$options['entity_id'] contains your id
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setRequired('entity_id');
    }
}

传递entity_id：

$form = $this->createForm(CFProgramLevelQuoteType::class, $entity, [
    'entity_id' => $entity_id
]);

Answer 2

这是完全有效的例子（非常类似于@striker）。如果您没有拼错，请仔细检查。否则请尝试php bin/console cache:clear

控制器动作：

public function testAction(Request $request)
{
    $form = $this->createForm(TestType::class, null, [
        'option1' => 6
    ]);
    return $this->render('default/test.html.twig',[
        'form' => $form->createView()
    ]);
}

TestType.php：

class TestType extends AbstractType
{
    /**
     * {@inheritdoc}
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('test', IntegerType::class, [
            'data' => $options['option1']
        ]);
    }

    /**
     * {@inheritdoc}
     */
    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setRequired('option1');
    }

    /**
     * {@inheritdoc}
     */
    public function getBlockPrefix()
    {
        return 'appbundle_test';
    }
}

如何使用FormBuilder将“额外”数据发送到Symfony 3.2.x表单？

2 个答案: