Question

我有一项技能SkillIntent，当你问一个关于特定游戏的问题时，它会回复该技能的描述。工作完美 - 但我现在要做的就是回答世卫组织的技巧，如果提出不同的要求。

以下是我的工作代码：

'use strict';

var AlexaSkill = require('./AlexaSkill'),
    descriptions = require('./descriptions');

var APP_ID = undefined;

var ZombicideSkills = function () {
    AlexaSkill.call(this, APP_ID);
};

// Extend AlexaSkill
ZombicideSkills.prototype = Object.create(AlexaSkill.prototype);
ZombicideSkills.prototype.constructor = ZombicideSkills;

ZombicideSkills.prototype.eventHandlers.onLaunch = function (launchRequest, session, response) {
    var speechText = "You can ask a question like, what does this skill do? ... Now, what can I help you with.";

    var repromptText = "For instructions on what you can say, please say help me.";
    response.ask(speechText, repromptText);
};

ZombicideSkills.prototype.intentHandlers = {
    "SkillIntent": function (intent, session, response) {
        var skillSlot = intent.slots.Skill,
            skillName;
        if (skillSlot && skillSlot.value){
            skillName = skillSlot.value.toLowerCase();
        }

        var cardTitle = "Description for " + skillName,
            description = descriptions[skillName],
            speechOutput,
            repromptOutput;
        if (description) {
            speechOutput = {
                speech: description,
                type: AlexaSkill.speechOutputType.PLAIN_TEXT
            };
            response.tellWithCard(speechOutput, cardTitle, description);
        } else {
            var speech;
            if (skillName) {
                speech = "I'm sorry, I don't know if I know " + skillName + ". What else can I help with?";
            } else {
                speech = "I'm sorry, I currently do not know that skill. What else can I help with?";
            }
            speechOutput = {
                speech: speech,
                type: AlexaSkill.speechOutputType.PLAIN_TEXT
            };
            repromptOutput = {
                speech: "What else can I help with?",
                type: AlexaSkill.speechOutputType.PLAIN_TEXT
            };
            response.ask(speechOutput, repromptOutput);
        }
    },

    "AMAZON.StopIntent": function (intent, session, response) {
        var speechOutput = "Goodbye";
        response.tell(speechOutput);
    },

    "AMAZON.CancelIntent": function (intent, session, response) {
        var speechOutput = "Goodbye";
        response.tell(speechOutput);
    },

    "AMAZON.HelpIntent": function (intent, session, response) {
        var speechText = "You can ask questions such as, what does this skill do, or, you can say exit... Now, what can I help you with?";
        var repromptText = "You can say things like, what does this skill do, or you can say exit... Now, what can I help you with?";
        var speechOutput = {
            speech: speechText,
            type: AlexaSkill.speechOutputType.PLAIN_TEXT
        };
        var repromptOutput = {
            speech: repromptText,
            type: AlexaSkill.speechOutputType.PLAIN_TEXT
        };
        response.ask(speechOutput, repromptOutput);
    }
};

exports.handler = function (event, context) {
    var zombicide = new ZombicideSkills();
    zombicide.execute(event, context);
};

它的模拟方式与MC Helper非常相似。我是否只需实现一个名为＆＃39; ActorIntent＆＃39;的其他intentHandlers。然后在Utterences中指定ActorIntent what {actors} have the {skill} skill?

我一直在玩这个想法，但我还不太清楚如何使用Lambda函数进行故障排除 - 只需上传并查看端点可以到达＆＃39;。

如果我必须拥有两种不同的技能，那会很烦人，但我不确定？这只是我的代码库的一个问题，我应该可以创建一个ActorIntent而不会出问题吗？

Answer 1

定义不同的Intent，例如Update slots SET locked = false WHERE `datetime`> NOW() - INTERVAL 15 MINUTE; SELECT * FROM slots WHERE locked = false;，并在Alexa Developer Portal的交互模型中，定义该意图的话语。你绝对不需要为此做另一项技能。

Answer 2

具有良好用户体验的解决方案如下：

用户询问触发SkillIntent的游戏技能

在您的代码中：将此技能保存在变量中（例如，作为字符串）
Alexa会告诉您的技能说明，并可能会提出进一步的问题。
用户现在可以问：哪些演员有此技能？这会触发你的意图ActorIntent。

话语：ActorIntent哪些演员有这种技能？
您知道用户正在谈论的技能（因为您将其存储在变量中）。现在alexa可以告诉具体的演员。

意图架构示例：

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <time.h>

int main()
{
  int n = 0;
  srand(time(NULL)); // seed for rand

  for (int c = 1; c <= 10; c++)
   {
     n = rand() % 25 + 97; // rand() gives you a number between 0 and 24 and then add 98 to get a number between 97 and 122
     printf("%d\n", n);
   }
}

使用一个Alexa技能进行不同的调用

2 个答案: