Question

我正在制作一个触发器，检查一个人是否可以去世界或欧洲锦标赛，如果他们开车去计算他们花在燃料上的费用（燃料成本*花费*距离/ 100）。我需要将该信息放在另一个表中，但我收到了这条消息：

Error(24,66): PL/SQL: ORA-00984: column not allowed here

那是因为我在代码底部的INSERT语句中加了“fuelcost *花费*：new.distance / 100”。我的问题是，我怎样才能以不同的方式将这个价值放在表格成本中。 Column costs.money不是计算列，因为它不仅仅是该表中的燃料成本，因此这不是解决方案。

CREATE OR REPLACE TRIGGER check_norm_fuel_cost 
  INSTEAD OF INSERT OR UPDATE ON insert_travel_view
  FOR EACH ROW
  DECLARE 
    hasnorm char(1);
    spends number;
    fuelcost number;

  BEGIN
    SELECT norms.norm INTO hasnorm
      FROM norms JOIN competitions
        ON competitions.competitionID=norms.competitionID
      WHERE :new.personID = norms.personID 
           AND (competitions.name LIKE 'European championship' 
              OR competitions.name LIKE 'World championship');

      IF hasnorm = 'Y' OR hasnorm IS NULL THEN
        INSERT INTO travel(travelID, personID, competitionID, vehicleID, distance) 
          VALUES (:new.travelID, :new.personID, :new.competitionID, :new.vehicleID, :new.distance);
        IF :new.distance IS NOT NULL THEN
          SELECT vehicles.consumption INTO spends FROM vehicles 
            WHERE :new.vehicleID = vehicles.vehicleID;
          SELECT fuels.cost INTO fuelcost FROM fuels JOIN vehicles ON vehicles.fuelID = fuels.fuelID
            WHERE :new.vehicleID = vehicles.vehicleID;

          INSERT INTO COSTS(costID, costtype, travelID, money)
            VALUES(35, 'fuel', :new.travelID, fuelcost*spends*:new.distance/100);

        END IF;
      END IF;
  END;

Answer 1

尝试将insert语句中的显式值更改为选择插入（...）选择....来自，抱歉从移动设备写错了格式。

Answer 2

你似乎有三个问题; ORA-00984是因为您的最终插入正在执行：

VALUES(35, 'fuel', :new.travelID, fuelcost*spends*distance/100);

其中distance被解释为列名，因为范围内没有该名称的变量;它可能应该是：

VALUES(35, 'fuel', :new.travelID, fuelcost*spends*:new.distance/100);

虽然您可以避开spends和fuelcost局部变量，而是执行insert ... select：

INSERT INTO COSTS(costID, costtype, travelID, money)
SELECT 35, 'fuel', :new.travelID, fuels.cost*vehicles.consumption*:new.distance/100
FROM fuels JOIN vehicles ON vehicles.fuelID = fuels.fuelID
WHERE vehicles.vehicleID = :new.vehicleID;

你也有两个拼写错误：

    INSERT INTO travel(travelID, personID, competitonID, vehicleID, distance)

缺少i，应该（我认为）是：

    INSERT INTO travel(travelID, personID, competitionID, vehicleID, distance)

和

        WHERE :new.vehicleID = vehicle.vehicleID;

缺少s，应该（我认为）是：

        WHERE :new.vehicleID = vehicles.vehicleID;

错误（24,66）：PL / SQL：ORA-00984：此处不允许列

2 个答案: