Question

如何使用javascript获取价格最高的对象：

我有这段代码，但效果不好

var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}];
var biggestNumber = 0;
for (var i = 0; i < array.length; i++){
    var item = array[i]
  if(biggestNumber < item.Price) {
    biggestNumber = item;
  }
}
console.log(biggestNumber);

Answer 1

let highestPrice = Math.max.apply(null, array.map(e => e.Price));
let item = array.find(e => e.Price === highestPrice);

Answer 2

＆＃13;

var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}];

var maxIndex = 0;                             // assume the max is at 0
for(var i = 1; i < array.length; i++) {       // for the rest of the objects in the array
  if(array[i].Price > array[maxIndex].Price)  // if the current object is bigger than the assumed max
    maxIndex = i;                             // then this current object's index is the new maxIndex
}

var maxObject = array[maxIndex];              // max object is the object at maxIndex
console.log(maxObject);

＆＃13;

Answer 3

您可以使用Array.prototype.reduce来减少＆＃34;将整个数组转换为单个值：价格最高的对象。

var itemWithHighestPrice = array.reduce(function(highest, item, index) {
    if (index === 0 || item.Price > highest.Price) {
        return item;
    }
    return highest;
}, {});

Answer 4

你必须将item.Price存储在largestNumber而不是item。

var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}];
var biggestNumber = 0;
for (var i = 0; i < array.length; i++){
    var item = array[i]
  if(biggestNumber < item.Price) {
    biggestNumber = item.Price;
  }
}
console.log(biggestNumber);

Answer 5

使用for statement的经典方法。

此提议将第一个元素作为临时结果，并使用结果检查数组的所有后续对象。如果找到更大的Price，则result将更改为实际元素。

var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }],
    result = array[0],                   // take the first element
    i;

for (i = 1; i < array.length; i++) {     // iterate from the second on
    if (array[i].Price > result.Price) { // check price, if a greater price found
        result = array[i];               // replace result with actual object
    }
}

console.log(result);

或者您可以使用Array#reduce并在回调中返回检查结果。

var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }],
    result = array.reduce(function (a, b) {
        return a.Price > b.Price ? a : b;
    }, {});

console.log(result);

与ES6相同

var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }],
    result = array.reduce((a, b) => a.Price > b.Price ? a : b, {});

console.log(result);

Answer 6

var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}];
var biggestNumber = {Price:0};
array.forEach(function(obj){
if(obj.Price>biggestNumber.Price)
   biggestNumber=obj;
});
console.log(biggestNumber);

Answer 7

<强>问题：

您的问题是，您要将整个item对象存储在highestPrice变量中，然后尝试将Number与object进行比较。

<强>解决方案：

您应该只在item.Price变量中存储highestPrice并比较Price值，然后像这样编辑代码：

var biggestNumber = 0;
for (var i = 0; i < array.length; i++) {
  var item = array[i];
  if (biggestNumber < item.Price) {
    biggestNumber = item.Price;
  }
}

工作代码段

＆＃13;

var array = [{
  Name: "blue",
  Price: 20
}, {
  Name: "red",
  Price: 10
}, {
  Name: "green",
  Price: 30
}];


var biggestNumber = 0;
for (var i = 0; i < array.length; i++) {
  var item = array[i];
  if (biggestNumber < item.Price) {
    biggestNumber = item.Price;
  }
}

console.log(biggestNumber);

＆＃13;

注意：

如果你想要整个item作为结果，你只需要比较两个对象Price属性，更新你的第一个代码：

for (var i = 0; i < array.length; i++){ var item = array[i] if(biggestNumber.Price < item.Price) { biggestNumber = item; } }

从价格最高的数组中获取对象

7 个答案: