Question

不确定此脚本有什么问题

$SSODelete= "Delete"
$SSOfiles = "SSo.xml" 
$channlename = "INC8-Patch"
write-host $channlename
if ($channelname -like *INC8*){ 
   $SSOarg = "$SSODelete $SSOfiles"
   Write-Host $SSOarg
}

它抛出以下错误：

You must provide a value expression following the '*' operator.
At line:5 char:25
+ if ($channelname -like *INC8*){
+                         ~~~~~
Unexpected token 'INC8*' in expression or statement.

尝试使用"*INC8*"和'*INC8'，但它不符合if声明。

为脚本添加屏幕截图及其结果 Simple Script and results

Answer 1

PowerShell -like运算符应与引用的匹配字符串一起使用，例如$variable -like "*pattern*"。 -like仅接受简单通配符（*）;您可以使用-match与正则表达式（regexps）进行比较。请参阅Get-Help about_Comparison_Operators。

Answer 2

谢谢，这是由于变量名称我正在比较......我需要更加谨慎

PowerShell if -like错误

2 个答案: