Question

在这个sql中，我只想查看＆＃34; ON＆＃34; b.block =＆＃39; False＆＃39;。因为有时＆＃34; profileview＆＃34;表值为空。我只想要，如果user_fullinfo值在profileview中与此条件匹配，则b.block =＆＃39; False＆＃39;它应该是显示，如果在配置文件视图中没有值，那么它也应该显示，

SELECT  a.* FROM user_fullinfo a left join profileview b on
CASE
WHEN a.id=b.rid and b.rid='105' THEN 
b.block='False' 
END
where gender != 'Male' and (DATEDIFF(YY,dob,GETDATE()) Between '10' and '100') and (a.heightid between 58 and 65) and( a.complexionid = '3' or a.complexionid = '4' or a.complexionid = '5') and a.bodytypeid = '4' and a.marital_statusid = '3'

它说sql错误（102）：＆＃34; =＆＃34; ...附近的语法不正确请给出解决方案..

Answer 1

布尔表达式不适合作为值，例如case的值。我的建议是完全删除case并使用布尔逻辑。像这样：

select a.*
from user_fullinfo a left join
     profileview b
     on (a.id = b.rid and b.rid = '105' and b.block = 'False') or 
        ( not (a.id = b.rid and b.rid = '105' and b.block = 'False') and
          gender <> 'Male' and (datediff(year, dob, getdate()) Between 10 and 100) and
          (a.heightid between 58 and 65) and
          (a.complexionid in (3, 4, 5)) and
          a.bodytypeid = 4 and a.marital_statusid = 3
        );

注意：

SQL中SQL不等式的标准是<>，尽管!=也被广泛接受。
不要在数字常量周围使用单引号。 between '10' and '100'与between 10 and 100不同。
我怀疑这个版本或你的case版本真的能做到你想要的。对于第二个条件，两个表之间没有相关性。

这应解决您的语法问题。逻辑问题是一个不同的问题。我建议您询问另一个问题，包括样本数据，期望，结果和逻辑解释。

Answer 2

正如你在case语句中只有1个条件，你可以使用直接连接，如下面的

jobname     | jobid | Action
sendemail   | 34636 | Button(Name Retry)
sendereport | 35455 | Button(Name Retry)

如果您有任何其他需要添加的案例陈述，您可以像这样更改ON语句

SELECT  
    a.* 
    FROM user_fullinfo a 
        LEFT JOIN profileview b 
            ON a.id = b.rid 
                AND b.rid ='105' 
                AND b.block ='False' 
        WHERE gender <> 'Male' 
            AND (DATEDIFF(YY,dob,GETDATE()) BETWEEN '10' AND '100') 
            AND (a.heightid between 58 and 65) 
            AND 
            (
                a.complexionid = '3' 
                OR 
                a.complexionid = '4' 
                OR 
                a.complexionid = '5'
            ) 
            AND a.bodytypeid = '4' 
            AND a.marital_statusid = '3'

Sql错误说＆＃34;语法错误＆＃34; =＆＃34;

2 个答案: