Question

我有以下C ++，两个函数都返回int 0，表示成功。

#include "stdafx.h"
#include <iostream>
#include "scapi.h"


int main() {

    int ret;

    ret = sc_LoginByLogon(L"hostname.domain.ltd", L"admin", L"pass");
    std::cout << "LoginByLogon: " << ret << std::endl;

    void* out_p;

    ret = sc_GetUserInfoByUserLogon(L"username", &out_p);
    std::cout << "GetUserInfoByUserLogon: " << ret << std::endl;
}

我现在正在尝试使用Python为这两个函数创建一个包装器，并提出以下代码：

import sys
import ctypes
from ctypes import *

# Load DLL into memory.
class SUserInfoApiV4(Structure):
    INTRFDEF_SIZE_RESERVED = 32
    _fields_ = [
                 ('m_nStructLength', c_int),
                 ('m_nVersion', c_short),
                 ('m_nSubVersion', c_short),
                 ('m_achReserved', c_char * (INTRFDEF_SIZE_RESERVED - sizeof(c_long))),
                 ('m_nAccessRights', c_long),
                 ('m_nUserType', c_short),
                 ('m_nUserId', c_int),
                 ('m_nSubRights', c_long),
                 ('m_nNotUsed1', c_int),
                 ('m_wzFullName', c_wchar * 101),
                 ('m_wzDescription', c_wchar * 101),
                 ('m_wzEMail', c_wchar * 101),
                 ('m_wzUserLogon', c_wchar * 21),
                 ('m_wzPassword', c_wchar * 17),
                 ('m_szCardNo', c_char * 40),
                 ('m_szPINCode', c_char * 5),
                 ('m_szPUKCode', c_char * 9),
                 ('m_nLogonFails', c_short),
                 ('m_bUserLocked', c_short),
                 ('m_bUserDisabled', c_short),
                 ('m_bAvoidPin', c_short),
                 ('m_bPrintAll', c_short),
                 ('m_bCardOpen', c_short),
                 ('m_nBillingModel', c_short),
                 ('m_nAccountingModel', c_short),
                 ('m_nUserRights', c_int),
                 ('m_bAllowEncryption', c_short),
                 ('m_bAllowCheckPrinting', c_char),
                 ('m_bAllowPmail', c_char),
                 ('m_bDenyRetain', c_char),
                 ('m_lCreationDate', c_long),
                 ('m_lLastLogin', c_long),
                 ('m_nServerId', c_int),
                 ('m_nDomainId', c_int),
                 ('m_nTreeNodeId', c_int),
                 ('m_nNid', c_int),
                 ('m_wzCostCode', c_wchar * 51)
    ]

def main(argv):
    # import library
    lib = ctypes.cdll.LoadLibrary('scAPI.dll')

    # login
    login = lib.sc_LoginByLogon('hostname.domain.ltd', 'admin', 'pass')

    # sc_GetUserInfoByUserLogon
    SUserInfoApiV4p = POINTER(SUserInfoApiV4)
    sc_GetUserInfoByUserLogon = lib.sc_GetUserInfoByUserLogon
    sc_GetUserInfoByUserLogon.argtypes = [c_wchar_p, POINTER(SUserInfoApiV4p)]
    sc_GetUserInfoByUserLogon.restype = c_int

    # get user object
    out_p = SUserInfoApiV4p()
    user = sc_GetUserInfoByUserLogon('username', byref(out_p))

    # debug
    print 'LoginByLogon: ' + str(login)
    print 'GetUserInfoByUserLogon: ' + str(user)
    #print 'Full name:', out_p.contents.m_wzFullName

if __name__ == '__main__':
    main(sys.argv)

代码应该有效，但在Python中，只有sc_LoginByLogon返回0而sc_GetUserInfoByUserLogon失败（1）。 The documentation仅表示“1 =一般失败”，所以我被卡住了。

任何明显的想法都会受到高度赞赏。

Answer 1

感谢Mark Tolonen，它现在可以在调用之前显式定义登录函数。我没想过，因为它已经返回0表示成功。

唯一的问题是所有属性，例如＆＃34; m_wzFullName＆＃34;因某种原因跳过第一个角色。

修改由于这个线程，我解决了最后一个bug： python ctypes pragma pack for byte aligned read

# sc_LoginByLogon sc_LoginByLogon = lib.sc_LoginByLogon sc_LoginByLogon.argtypes = [c_wchar_p, c_wchar_p, c_wchar_p] sc_LoginByLogon.restype = c_int

使用ctypes在Python中使用C ++代码

1 个答案: