我正在尝试在Mongo DB中创建一个文档,其中包含一个嵌入式文档。该文档的模型/架构如下:
var mongoose = require('mongoose');
var Schema = mongoose.Schema;
// Cupboard Collection Schema
var ShelfSchema = new Schema({
shelf_name: {
type: String
},
shelf_desc: {
type: String
}
});
var CupboardSchema = new Schema({
cupboard_name: {
type: String,
required: true,
unique: true
},
cupboard_desc: {
type: String,
required: true
},
shelf: [ShelfSchema]
},
{
timestamps: true
});
module.exports = mongoose.model('Cupboard', CupboardSchema);
当我打印" newCupboard"在控制台中,我按照以下格式获取文档:
{
_id: 58e4b972931dc809f4127b0b
cupboard_name: Cupboard A,
cupboard_desc: Cupboard A Details,
shelf: [ {
shelf_name: Cupboard A,
shelf_desc: Cupboard A Details,
_id: 58e4c2742bfc0111dc47f149
}]
}
但执行后,嵌入式文档没有被保存。没有显示错误。最终结果如下所示:
{
_id: 58e4b972931dc809f4127b0b
cupboard_name: Cupboard A,
cupboard_desc: Cupboard A Details
}
任何人都可以帮我解决这个问题,为什么嵌入式文档没有保存在mongo db中?
感谢。
答案 0 :(得分:1)
您不将嵌入文档作为整个文档保存在另一个文档中。您必须保存文档的“_id”,并且在获取记录时,您将在查询中调用populate()
。
所以,让我们假设您必须在Cupboard架构中保存文档,架构将如下所示 -
var CupboardSchema = new Schema({
cupboard_name: {
type: String,
required: true,
unique: true
},
cupboard_desc: {
type: String,
required: true
},
shelf: {
type: Schema.Types.ObjectId,
ref: 'ShelfSchema'}
},
{
timestamps: true
});
现在,在'shelf'保存您要填充的相应文档。当您要获取文档时,请致电populate()
,如 -
CupboardSchemaModel.find({_id: <some-id-you-want-to-fetch>}).populate('shelf');