$ in表示多个值

Question

var footballerIdToPassive = "qqqqq";
var footballerlevelToPassive = ["3052002","3052003"];

db.goals.find({ "footballer": footballerIdToPassive, "footballerlevel": { $in: [footballerlevelToPassive]}}))

因为它只带来了目标db shell，当我运行计数时，count是1

{ "footballer": "qqqqq", "footballerlevel": "3052002" }

也适用于

var footballerlevelToPassive = "3052002";

这个，它有效。但我无法做到多重。我可以做这项工作吗？

我需要使用每个，我需要更新每个

Answer 1

footballerlevelToPassive已经是一个数组，您无需再次在查询中将其包装在另一个数组中，只需将其$in直接引用为

var footballerIdToPassive = "qqqqq";
var footballerlevelToPassive = ["3052002","3052003"];

db.goals.find({ 
    "footballer": footballerIdToPassive, 
    "footballerlevel": { "$in": footballerlevelToPassive }
})

等同于查询

db.goals.find({ 
    "footballer": footballerIdToPassive, 
    "$or": [
        { "footballerlevel": "3052002" },
        { "footballerlevel": "3052003" }
    ]
})

快速演示