Question

传入的“types”参数格式为["hourAverage","hourMedian","dayAverage","dayMedian","weekAverage","weekMedian","monthAverage","monthMedian"]

来源：

$scope.buildCharts = function(types){
    var deferred = $q.defer();
    var promises = [];

    types.forEach(function(type){
                $scope.prepareData(type);
                deferred.resolve([
                {
                    title: type,
                    curveType: 'function',
                    legend: { position: 'bottom' }
                },type]);
                promises.push(deferred.promise);
    });
    return $q.all(promises);
};

输出：

[
  [
    {
      "title": "hourAverage",
      "curveType": "function",
      "legend": {
        "position": "bottom"
      }
    },
    "hourAverage"
  ],
  [
    {
      "title": "hourAverage",
      "curveType": "function",
      "legend": {
        "position": "bottom"
      }
    },
    "hourAverage"
  ],
  [
    {
      "title": "hourAverage",
      "curveType": "function",
      "legend": {
        "position": "bottom"
      }
    },
    "hourAverage"
  ],
  [
    {
      "title": "hourAverage",
      "curveType": "function",
      "legend": {
        "position": "bottom"
      }
    },
    "hourAverage"
  ],
  [
    {
      "title": "hourAverage",
      "curveType": "function",
      "legend": {
        "position": "bottom"
      }
    },
    "hourAverage"
  ],
  [
    {
      "title": "hourAverage",
      "curveType": "function",
      "legend": {
        "position": "bottom"
      }
    },
    "hourAverage"
  ],
  [
    {
      "title": "hourAverage",
      "curveType": "function",
      "legend": {
        "position": "bottom"
      }
    },
    "hourAverage"
  ],
  [
    {
      "title": "hourAverage",
      "curveType": "function",
      "legend": {
        "position": "bottom"
      }
    },
    "hourAverage"
  ]
]

Answer 1

这表明承诺只能用一个值来解决。 resolve对同一延迟对象的进一步调用将不起作用。这就是为什么你一遍又一遍地将第一个对象作为值。这是Promises/A+ specifications, point 2.1.2（强调我的）所需的行为：

2.1.2满足后，承诺：

2.1.2.1不得过渡到任何其他州。

2.1.2.2必须有一个值，不得更改。

当然，如果允许更改承诺的值，那么你仍然不会得到所需的结果，因为结果会重复< em> last 对象值。

要解决此问题，请在循环中创建一个新的延迟对象，以便始终解决新的承诺：

移动它：

var deferred = $q.defer();

进入forEach回调：

types.forEach(function(type){ var deferred = $q.defer(); // etc...

对于每个循环，承诺不在angularjs中

1 个答案: