没有搜索第一个字母

时间:2017-04-05 04:04:55

标签: ios swift uitableview plist uisearchbar

我正在将我的plist加载到TableView中,一切正常,但现在当我搜索某些内容时,它不会考虑第一个字母。您可以在下面看到directory.plist和我的Main.storyboard

plist and storyboard

要正确加载plist,我将以下代码放在didFinishLaunchingWithOptions

class AppDelegate: UIResponder, UIApplicationDelegate {

    var window: UIWindow?

    func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
        if let url = Bundle.main.url(forResource: "directory", withExtension: "plist"), let array = NSArray(contentsOf: url) as? [[String:Any]] {
            Shared.instance.employees = array.map{Employee(dictionary: $0)}
        }
        return true
}

我还有一个结构帮助我加载所有东西:

struct EmployeeDetails {
    let functionary: String
    let imageFace: String
    let phone: String

    init(dictionary: [String: Any]) {
        self.functionary = (dictionary["Functionary"] as? String) ?? ""
        self.imageFace = (dictionary["ImageFace"] as? String) ?? ""
        self.phone = (dictionary["Phone"] as? String) ?? ""
    }
}
struct Employee {
    let position: String
    let name: String
    let details: [EmployeeDetails] // [String:Any]

    init(dictionary: [String: Any]) {
        self.position = (dictionary["Position"] as? String) ?? ""
        self.name = (dictionary["Name"] as? String) ?? ""

        let t = (dictionary["Details"] as? [Any]) ?? []
        self.details = t.map({EmployeeDetails(dictionary: $0 as! [String : Any])})
    }
}

struct Shared {
    static var instance = Shared()
    var employees: [Employee] = []
}

直到这里,一切运行良好!现在我在尝试插入SearchView时遇到了麻烦,看看我到目前为止所做的事情:

class Page1: UITableViewController, UISearchBarDelegate {

    @IBOutlet weak var searchBar: UISearchBar!

    var employeesSearching = [Employee]()
    var isSearching : Bool = false

    override func viewDidLoad() {
        super.viewDidLoad()

        self.searchBar.delegate = self
    }

    override func numberOfSections(in tableView: UITableView) -> Int {
        return 1
    }

    override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        if self.isSearching == true {
            return self.employeesSearching.count
        } else {
            return Shared.instance.employees.count
        }
    }

    override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! TableViewCell1
        let employee = Shared.instance.employees[indexPath.row]

        if self.isSearching == true {
            cell.nameLabel.text = self.employeesSearching[indexPath.row].name
            cell.positionLabel.text = self.employeesSearching[indexPath.row].position
        } else {
            cell.nameLabel.text = employee.name
            cell.positionLabel.text = employee.position
        }
        return cell
    }

    func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
        if self.searchBar.text!.isEmpty {
            self.isSearching = false
            self.tableView.reloadData()
        } else {
            self.isSearching = true
            self.employeesSearching.removeAll(keepingCapacity: false)
            for i in 0..<Shared.instance.employees.count {
                let listItem : Employee = Shared.instance.employees[i]
                if listItem.name.range(of: self.searchBar.text!.lowercased()) != nil {
                    self.employeesSearching.append(listItem)
                }
            }
            self.tableView.reloadData()
        }
    }

    override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        if let destination = segue.destination as? Page2,
            let indexPath = tableView.indexPathForSelectedRow {
            destination.newPage = Shared.instance.employees[indexPath.row]
        }
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
    }
}

我在搜索的第一个字母上遇到了麻烦。看看:

enter image description here enter image description here

1 个答案:

答案 0 :(得分:2)

问题在于这一行:

if listItem.name.range(of: self.searchBar.text!.lowercased()) != nil {

您正在寻找员工姓名常规文本中的小写版本的搜索文本。

文本&#34; John Smith&#34;不包含搜索文本&#34; j&#34;。但它确实包含搜索文本&#34; ohn&#34;。

快速解决方法是将该行代码更改为:

if listItem.name.lowercased().range(of: self.searchBar.text!.lowercased()) != nil {

现在比较员工姓名和搜索文本的小写版本。所以现在它将匹配,因为&#34; john smith&#34;包含&#34; j&#34;。

BTW - 一遍又一遍地小写搜索文本效率很低。并且有更好的方法来编写循环代码。我会改为:

self.employeesSearching.removeAll(keepingCapacity: false)
let searchText = self.searchBar.text!.lowercased()
for employee in Shared.instance.employees {
    if employee.name.lowercased().range(of: searchText) != nil {
        self.employeesSearching.append(employee)
    }
}

更简单的方法是用以下代码替换代码:

let searchText = self.searchBar.text!.lowercased()
self.employeesSearching = Shared.instance.employees.filter { $0.name.lowercased().range(of: searchText) != nil
}

要在名称或位置搜索文本,只需更新比较表达式:

if employee.name.lowercased().range(of: searchText) != nil || employee.position.lowercased().range(of: searchText) != nil {

如果您使用filter,请进行类似的更改。