Question

我正在阅读带有'n'no的制表符分隔文件。对每行进行一些计算并将其打印到控制台。我面临的问题是某些行中的某些属性没有值并且具有空字符串。我想识别这样的空字符串并用零替换它们。这是我的代码和示例输入，如下所示。

代码： -

<p>
<!-- there is content omitted for brevity -->
  <span data-ng-repeat="life in data.list2 track by $index">

    <a class="pointer" ng-if="life.beneficiary.length > 0" ng-click="c.editBeneficiary(life)">

    <!-- content omitted for brevity-->
    </a>

    <a class="pointer" ng-if="!life.beneficiary.length" ng-click="c.addBeneficiary()">Add Beneficiary&nbsp;</a>

  </span>

</p>

输入： -

from datetime import datetime
import csv
with open('input1.txt') as inputfile:
    reader = csv.reader(inputfile,delimiter='\t')
    inputm = list(reader) #contents of csv   

for i in inputm[1:]:
    print('\n',str(datetime.strptime(i[0].split(':')[1], '%Y%m%d'))[:10] ,i[1],sum(map(float,i[2:6]))/4,i[6])

评论： - 第6行在第5个字段中有空格。需要识别这些字段并将其替换为零。

Answer 1

您可以使用列表推导来执行此操作，该列表推导允许您执行if / else条件。作为测试

$Users = gc "C:\scripts\Users.txt" 
$ADusers = Get-ADUser -Filter '*' -Properties DisplayName,SamAccountName,Enabled,MemberOf,PasswordNeverExpires,LockedOut |
    select DisplayName, SamAccountName, Enabled, MemberOf, PasswordNeverExpires, LockedOut 

$ADusers |
    ? { $Users -contains $_.SamAccountName } |
    Out-File c:\scripts\results\UserResults.txt

Compare-Object $ADusers.SamAccountName $users | 
    ? {$_.SideIndicator -eq =>} |
    Select-Object -ExpandProperty InputObject |
    Out-File c:\scripts\results\Failures.txt

将它放入你的代码中

>>> i = ['11', '', '3.3', '']
>>> sum(float(v) if v else 0.0 for v in i)
14.3

<强>更新

使用制表符显示示例可能很困难，因为stackoverflow会过滤掉它们。一种技术是编写一些将字节写入测试文件的代码，以便其他人可以运行它。下面是一个工作示例，显示from datetime import datetime import csv with open('input1.txt') as inputfile: reader = csv.reader(inputfile,delimiter='\t') inputm = list(reader) #contents of csv for i in inputm[1:]: print('\n', str(datetime.strptime(i[0].split(':')[1], '%Y%m%d'))[:10], i[1], sum(float(v) if v else 0.0 for v in i[2:6])/4,i[6])模块如何识别最后一行中有一个空制表符分隔的单元格，并用空字符串替换它。转换工作正常！

csv

输出：

# write a test file we can work with
open('mytest.csv', 'wb').write(
b"""1:20150501\t123\t10\t20\t0\t0\t'xyz'
2:20150501\t124\t0\t20.6\t90\t18.7\t'abc'
3:20150501:replacement\t123\t10.9\t20.3\t0\t80\t'def'
4:20150501\t134\t10\t20\t50.6\t0\t'ghi'
5:20150501\t126\t10.7\t26.8\t0\t0\t'jkl'
6:20150501\t123\t8.9\t20\t0\t\t'mno'""")

import csv

with open('mytest.csv', newline='') as fp:
    reader = csv.reader(fp, delimiter='\t', skipinitialspace=True)
    for row in reader:
        converted = [float(v) if v else 0.0 for v in row[1:5]]
        print(row, converted)

Answer 2

你不能只使用循环和条件吗？

for idx, val in enumerate(i)
  if i[idx].isspace():
    i[idx] = 0

这将进入你的'line'循环

for i in inputm[1:]:
  for idx, val in enumerate(i)
    if i[idx].isspace():
      i[idx] = 0
  print('\n',str(datetime.strptime(i[0].split(':')[1], '%Y%m%d'))[:10] ,i[1],sum(map(float,i[2:6]))/4,i[6])

检查空格并替换为零

2 个答案: