Question

我试图通过按周编号分组来显示sql查询，并显示一周的周末而不是一周的开始，但到目前为止，实现这一点是徒劳的。我怎么能这样做？

select extract(week from actual_sale_date) as week_number,
to_char(date_trunc('week',  actual_sale_date) as date, 'MM/dd/yyyy'), count(*)
from data
where project_id = 'ABC'
and actual_sale_date >= date_trunc('year',current_date)
group by rollup( (actual_sale_date))

结果：

week_number        date                 count  
   1             01/02/2017                2
   1             01/02/2017                1                    
   2             01/09/2017                1
   2             01/09/2017                1
   2             01/09/2017                1
   3             01/16/2017                3
   3             01/16/2017                1
                                           10

请求：

week_number                 week_ending                     count 
    1                        01/08/2017                       3
    2                        01/15/2017                       3
    3                        01/22/2017                       4
                                                              10

Answer 1

您按照actual_sale_date进行分组，因此一周的结果不会按周聚合。要获得周结束日期，请在周初添加6天。在rollup中使用week_number和周结束日期。

select extract(week from actual_sale_date) as week_number,
to_char(date_trunc('week', actual_sale_date) + interval '6' day,'MM/dd/yyyy'), 
count(*)
from data
where project_id = 'ABC'
and actual_sale_date >= date_trunc('year',current_date)
group by rollup((extract(week from actual_sale_date)
               ,to_char(date_trunc('week', actual_sale_date) + interval '6' day,'MM/dd/yyyy')))

按周数和周结束分组

1 个答案: