Question

我试图用.delete_if从数组中删除某些元素。例如，我希望从数组中删除以下内容

[83]＃[“CN = hhtest，OU =用户XXX，DC = XXX，DC = com”]，：cn =＆gt; [“hhtest”]，：sn =＆gt; [“test”]，：givenname =＆gt; [“hh”]，：的memberOf =＆GT; [ “CN = SSLVPN用户，CN =用户，DC = XXX，DC = COM”， “CN =管理员，CN =内藏，DC = XXX，DC = COM”]，：的UserPrincipalName =＆GT; [ “hhtest@XXX.com”]}＆GT; ]]

我试图用

删除它

  @ldap_result.delete_if { |cn| cn == 'hhtest' }

我也尝试过其他变种。注意 - 如果我在视图中执行@ ldap_result.class，它将返回`array'

如果我这样做

@ldap_result.delete_if { |cn| cn != 'hhtest' }

我最终得到一个似乎违反直觉的空数组。

Answer 1

对我的问题的评论让我觉得我走错了路。我最终没有使用delete_if。我做的是遍历从ldap直接提取的名称列表，然后检查ldap_exceptions表中是否有匹配的条目。我知道这不是很有效但我们最多只有100个用户可以通过，任何时候只有3或4个人会使用该应用程序。

  # ---------------------------------
    # this is where we build the operator list. The operator list is the users pulled from LDAP minus any user
    # names entered in the ldap exceptions table. Note - Case and spacing must match exactly with the users
    # you want to exclude.

    @ldap_exceptions = LdapException.all                                      # get all of the users in ldap exceptions.

    @operator_list = ["x"]                                                    # initialize @operator_list as an array.


    @ldap_names.each do |ldn|                                                 # ldap names comes from the application controller.
        @ldap_exception = LdapException.where("username like ?", ldn)         # See if there is an entry in the ldap exception table. This isn't very efficient but considering the number of ldap users,
                                                                              # it should be fine.
        if !@ldap_exception.present? then                                     # if the ldap user isn't in the ldap exceptions table write it to the array
            @operator_list = @operator_list + [ldn]                           # ldn has to be in [] or you get a string into an array error.
        end
    end

简而言之，我试图在一个哈希而不是数组的东西上做一个delete_if。这种方法有效。

delete_if不使用数组。

1 个答案: