Question

我有一个SQL查询，它正在获取如下结果：

[{"id":89,"sender_id":2,"reciever_id":1,"message":"no reply","deleted_at":null,"created_at":"2017-04-04 17:01:20","updated_at":"2017-04-04 17:01:20"},

{"id":88,"sender_id":1,"reciever_id":2,"message":"hiiiii","deleted_at":null,"created_at":"2017-04-04 16:59:47","updated_at":"2017-04-04 16:59:47"},

{"id":87,"sender_id":5,"reciever_id":1,"message":"hiiiii","deleted_at":null,"created_at":"2017-04-04 16:59:43","updated_at":"2017-04-04 16:59:43"},

{"id":86,"sender_id":1,"reciever_id":5,"message":"hiiii","deleted_at":null,"created_at":"2017-04-04 16:59:38","updated_at":"2017-04-04 16:59:38"},

{"id":85,"sender_id":1,"reciever_id":5,"message":"hiii vRUN\n","deleted_at":null,"created_at":"2017-04-04 16:10:51","updated_at":"2017-04-04 16:10:51"}]

但我只想要sender_id和reciever_id的唯一组合。我只需要5行中的2行，因为只有2行具有唯一的组合。像这样：

[{"id":89,"sender_id":2,"reciever_id":1,"message":"no reply","deleted_at":null,"created_at":"2017-04-04 17:01:20","updated_at":"2017-04-04 17:01:20"},

{"id":87,"sender_id":5,"reciever_id":1,"message":"hiiiii","deleted_at":null,"created_at":"2017-04-04 16:59:43","updated_at":"2017-04-04 16:59:43"},

我怎样才能做到这一点？

Answer 1

像这样添加 GROUP BY

SELECT * 
FROM yourTable
GROUP BY SUBSTRING_INDEX(SUBSTRING_INDEX( ,',',3),':',-1)

<强>样品

mysql> SELECT  SUBSTRING_INDEX(SUBSTRING_INDEX('[{"id":89,"sender_id":2,"reciever_id":1,"message":"no reply","deleted_at":null,"created_at":"2017-04-04 17:01:20","updated_at":"2017-04-04 17:01:20"},' ,',',3),':',-1) as result;
+--------+
| result |
+--------+
| 1      |
+--------+
1 row in set (0,00 sec)

mysql>

仅选择具有两列唯一组合的行

1 个答案: