Question

我曾尝试从Codegniter的文档中复制，但我无法使表单验证回调起作用。

我添加了帮助表单，url和库form_validation。它不起作用并且总是返回“false”

控制器

 public function addtest()
        {
            $this->load->helper(array('form', 'url'));

            $this->load->library('form_validation');

            $this->form_validation->set_rules('username', 'Username', 'callback_username_check');
            if($_SERVER['REQUEST_METHOD'] == 'POST')
            {
                 if ($this->form_validation->run() == TRUE)
                {
                       die('true');
                }
                else
                {
                       die('false');
                }
            }

            $this->template
                ->build('myform',array());
        }

    public function username_check($str)
    {
        if ($str == 'test')
    {
            return TRUE;
    }
    else
    {
            return FALSE;
    }
    }

查看

<form method="post" action="" class="form-horizontal form-label-left">
    <div class="col-xs-12 col-md-9">
        <div class="x_panel">
            <div class="form-group col-xs-12">
                <div class="col-xs-3">
                    <label class="control-label">Folder name</label>
                </div>
                <div class="col-xs-9">
                    <input type="text" name="username" value="" class="form-control " id="" placeholder="">
                </div>
            </div>
            <button type="submit" class="btn btn-success">Submit</button>
        </div>
    </div>
</form>

Answer 1

在Libraries.php中扩展form_validation库

<强> MY_Form_validation.php

SELECT 
    AVATAR.NAME 
FROM 
    AVATAR 
INNER JOIN 
    PLAYERAVATAR ON PLAYERAVATAR.AVATAR_ID = AVATAR.AVATAR_ID 
INNER JOIN 
    PLAYER ON PLAYER.PLAYER_ID = PLAYERAVATAR.PLAYER_ID
WHERE 
    PLAYER.ACTIVE = 1
AND 
    PLAYER.EMAIL LIKE 'a%' ;

Answer 2

我的控制器功能就像这样，它运行得很好。我已经自动加载了所有库

public function change_password()
{
    if($this->isLoggedin()){
        $data['title']='Change Password';
        if($_POST)
        {
            $config=array(
                array(
                    'field' => 'old_password',
                    'label' => 'Old Password',
                    'rules' => 'trim|required|callback_checkPassword'
                ),
                array(
                    'field' => 'password',
                    'label' => 'Password',
                    'rules' => 'trim|required'
                ),
                array(
                    'field' => 'conf_password',
                    'label' => 'Confirm Password',
                    'rules' => 'trim|required|matches[password]'
                )
            );
            $this->form_validation->set_rules($config);
            if ($this->form_validation->run() == false)
            {
                // if validation has errors, save those errors in variable and send it to view
                $data['errors'] = validation_errors();
                $this->load->view('change_password',$data);
            }
            else
            {
                // if validation passes, check for user credentials from database
                $this->Login_model->updatePassword($_POST['password'],$this->session->userdata['id']);
                $this->session->set_flashdata('log_success','Congratulations! Password Changed');
                redirect(base_url() . 'Login/dashboard');
            }

        }
        else
        {
            $this->load->view('change_password',$data);
        }
    }
    else
    {
        redirect(base_url().'Login');
    }

}

public function checkPassword($str)
{
    $check=$this->Login_model->checkPassword($str);
    if($check)
    {
        return true;
    }
    else
    {
        $this->form_validation->set_message('checkPassword', 'The Current Password you have provided is incorrect');
        return false;
    }
}

Answer 3

在HTML（添加ID字段）

中

<input type="text" name="username" value="" class="form-control " id="username" placeholder="">

<button type="submit" class="btn btn-success" id="submit">Submit</button>

在您的AJAX代码中

<script type="text/javascript">
    $(function(){
        $( "#submit" ).click(function(event)
        {
            event.preventDefault();
            var username= $("#username").username();

            $.ajax(
                {
                    type:"post",
                    url: "<?php echo base_url(); ?>index.php/controller/Method",
                    data:{ username:username},
                    success:function(res)
                    {

                    }
                });
        });
    });
</script>>

在控制器中

无需检查if($_SERVER['REQUEST_METHOD'] == 'POST') cz它总是来自

public function addtest()
{
    $this->load->helper(array('form', 'url'));

    $this->load->library('form_validation');

    $this->form_validation->set_rules('username', 'Username', 'callback_username_check');

        if ($this->form_validation->run() == TRUE)
        {
            die('true');
        }
        else
        {
            die('false');
        }

    $this->template->build('myform',array());
}


public function username_check($str)
{
    if (empty($str)) 
    {
        echo "Empty";
    } 
    else 
    {
        if ($str == 'test')
        {
            return TRUE;
        }
        else
        {
            return FALSE;
        }
    }
}

查看有关Codeigniter CallBack Functon

的更多信息

Codeigniter - 我的表单验证回调不起作用

3 个答案: