Question

我无法从JSP下面传递userName并在Servlet过滤器中访问它。以下是JSP＆amp;过滤。我尝试使用请求Paramter，属性和ParameterNames访问，但只获取空值。我已经在调试模式下运行应用程序，在按下提交按钮后它正在点击过滤器。如果我做错了，请告诉我。 JSP：

 <html>
    <meta http-equiv="Content-Type" content="text/html; charset=US-ASCII">
        <head>

        </head>
        <body>
            <p><bean:message key="logonForm.info.text"/></p>
            <form action="/uchpweb/login.do" name="login_form" method="post">
                <div id="layLogInContainer">
                    <div id="layLogInFields" class="inputAreaLight">
                        <b>UserName</b><br>
                        <input type="text" name="username" id="username" tabindex="1" size="10" maxlength="10" /><br />
                    </div>
                    <div id="layLogInButtonBar" class="btnBar">
                        <input type="submit" name="submit" value="submit"/>
                    </div>
                </div>
            </form>
        </body>
    </html>`

过滤器：

public class UserFilter implements Filter {

    FilterConfig config;
    Boolean flag;

    @SuppressWarnings("unused")
    private Logger log = ResourceLocator.getInstance().getLogger(this);

    public void init(FilterConfig config) {
        this.config = config;
    }

    @SuppressWarnings("unchecked")
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {


        HttpServletRequest httpRequest = (HttpServletRequest) request;
        HttpSession httpSession = httpRequest.getSession();


        Enumeration<String> params = httpRequest.getParameterNames();
        while(params.hasMoreElements()){
            String name = params.nextElement();
            String value = request.getParameter(name);
            log.debug("Name : ",name);
            log.debug("value : ",value);
        }

        if (request.getParameter("username") == null && (request.getAttribute("username") == null)) {
            RequestDispatcher dispatcher1 = request.getRequestDispatcher("/logon.jsp");
            if (dispatcher1 != null) {
                dispatcher1.forward(request, response);
                return;
            }
        }
    }

的web.xml

  <filter>
    <filter-name>CommonUserContextFilter</filter-name>
    <filter-class>UserContextFilter</filter-class>
  </filter>
  <filter-mapping>
    <filter-name>CommonUserContextFilter</filter-name>
    <url-pattern>*.do</url-pattern>
  </filter-mapping>
  <filter-mapping>
    <filter-name>CommonUserContextFilter</filter-name>
    <url-pattern>/*</url-pattern>
  </filter-mapping>
  <filter-mapping>
    <filter-name>CommonUserContextFilter</filter-name>
    <url-pattern>*.jsp</url-pattern>
  </filter-mapping>

***Please click on this link to find httpRequest***

无法从JSP获取Servlet过滤器中的请求参数

0 个答案: