我有一个文本区域,我点击按钮添加订单列表项目。这是我的代码,
var addListItem = function() {
if (!this.addListItem.num) {
this.addListItem.num = 0
}
++this.addListItem.num;
var text = document.getElementById('editor').value;
console.log('text', text);
var exp = '\n' + this.addListItem.num + '.\xa0';
text = text.concat(exp);
document.getElementById('editor').value = text;
}
<div>
<button onclick="addListItem()">NumberList</button>
<textarea id="editor" col=10 rows=10></textarea>
</div>
答案 0 :(得分:0)
var addListItem = function() {
if (!this.addListItem.num) {
this.addListItem.num = 0
}
++this.addListItem.num;
var text = document.getElementById('editor').value;
//HERE start new counting if textarea is empty
if(text.trim() == ''){
this.addListItem.num = 1; //restart counting here
}
//else check if textarea has previous numbers to proceed counting
else {
var lastLine = text.substr(text.lastIndexOf("\n") + 1).trim();
this.addListItem.num = parseInt(lastLine.slice(0, -1)) + 1; //add 1 to last number
}
console.log('text', text);
var exp = '\n' + this.addListItem.num + '.\xa0';
text = text.concat(exp);
document.getElementById('editor').value = text;
}
<div>
<button onclick="addListItem()">NumberList</button>
<textarea id="editor" col=10 rows=10></textarea>
</div>
答案 1 :(得分:0)
您可以尝试这样的事情:
.
。 注意:此逻辑假定最后一个值为最大值。如果您希望处理该问题,则只需比较n
和parseInt
并指定最大值
<强>示例:强>
var addListItem = function() {
var text = document.getElementById('editor').value;
var exp = '\n' + (getLastNumber(text) + 1) + '.\xa0';
text = text.concat(exp);
document.getElementById('editor').value = text;
}
function getLastNumber(str){
var list = str.split(/[\r\n]/g);
var n = 0;
list.forEach(function(s){
if(/^\d+\./.test(s)){
n = parseInt(s.substring(0, s.indexOf(".")));
}
});
return n;
}
&#13;
<div>
<button onclick="addListItem()">NumberList</button>
<textarea id="editor" col=10 rows=10></textarea>
</div>
&#13;
答案 2 :(得分:0)
如果您想要一个处理各种不同情况的更强大的解决方案,您可以使用正则表达式来检测列表中的数字。
此解决方案还允许用户输入他们自己的号码,按钮点击“仍然无效!”
那是因为这个解决方案使用文本区域内容作为事实来源,而不是跟踪侧面的状态。
var addListItem = function() {
var text = document.getElementById('editor').value;
// regex to match against any new line that has a number and a period
// and extracts the number. feel free to use regex101.com to understand
// this in more depth.
var listNumberRegex = /^[0-9]+(?=\.)/gm;
var existingNums = [];
var num;
// get all the matches
while ((num = listNumberRegex.exec(text)) !== null) {
existingNums.push(num);
}
// sort the values
existingNums.sort();
// use the existing biggest number + 1 or use 1.
var addListItemNum;
if (existingNums.length > 0) {
// get last number and add 1
addListItemNum = parseInt(existingNums[existingNums.length - 1], 10) + 1;
} else {
// otherwise if there's nothing, just use 1.
addListItemNum = 1;
}
var exp = '\n' + addListItemNum + '.\xa0';
text = text.concat(exp);
document.getElementById('editor').value = text;
}
<div>
<button onclick="addListItem()">NumberList</button>
<textarea id="editor" col=10 rows=10></textarea>
</div>
理解正则表达式很棘手,随时可以查看https://regex101.com/r/gyX7oO/1以更好地了解正在发生的事情。