laquvel中jquery.js 9557错误

时间:2017-04-04 04:06:57

标签: php jquery laravel syntax-error

这是我需要在ajax中做出回应的函数

function load_id_user(id) {
    var CSRF_TOKEN = $('meta[name="csrf-token"]').attr('content');
    alert(id);

    $.ajax({
        url: 'load-user',
        type: 'POST',
        data: {_token: CSRF_TOKEN,id:id},
        success: function (data) {
           $( "#user_fields" ).html( data );
        }
    });
}

这是我的路线。

Route::post('load-user','UserController@load_id');

这是我的控制器

public function load_id() {
    $var=DB::select('select * from user where user_id="$_POST[id]"');

    //$var=Usuarios::select()->where("user_id","=",$_POST['id'])->get();
    foreach ($var as $user) {
        echo '<input type="text" name="cedula" value="'.$user->user_id.'" onblur="load_id_user(this.value);" placeholder="Cedula" class="form-control" required>';
    }
}

当我尝试运行此操作时,控制台说出错误500,尝试所有操作并且没有任何作用。

1 个答案:

答案 0 :(得分:0)

尝试将控制器代码更改为

public function load_id (Request $request) {

    $id = $request->input('id');
    $response = '';

    $var = Usuarios::where("user_id", "=", $id)->get();

    foreach ($var as $user) {
        $response .= '<input type="text" name="cedula" value="'.$user->user_id.'" onblur="load_id_user(this.value);" placeholder="Cedula" class="form-control" required>';
    }

    return $response;
}

和你的ajax请求

$.ajax({
    url: window.location.origin + '/load-user',
    type: 'POST',
    data: {
        _token: CSRF_TOKEN,
        id:id
    },
    success: function (data) {
        $( "#user_fields" ).html( data );
    }
});