无法找到问题,现在已经尝试了一段时间
CREATE
TRIGGER `checkin_enforcement` BEFORE INSERT
ON `booking`
FOR EACH ROW BEGIN
IF (NEW.checkinDate < NEW.checkoutDate) THEN
INSERT INTO booking (bookingID, hotelNo, guestNo, checkinDate, checkoutDate, roomNo) VALUES (NEW.bookingID, NEW.hotelNo, NEW.guestNo, NEW.checkinDate, NEW.checkoutDate, NEW.roomNo);
ELSE
signal sqlstate '45000' set message_text = 'The checkin date must be less than the checkout date!';
END IF;
END$$
#1064 - 您的SQL语法出错;查看与您的MySQL服务器版本相对应的手册,以获得在&#39;&#39;附近使用的正确语法。第7行
答案 0 :(得分:0)
如果条件通过,您不需要插入行。你只需要在没有错误时抛出错误。
此外,我将on insert
更改为on insert or update
,因为您可能希望即使在表中插入数据后仍然强制执行此规则。如果没有,只需将其更改为on insert
。
试试这个:
delimiter $$
create trigger checkin_enforcement
before insert or update on booking
for each row
begin
if (new.checkindate >= new.checkoutdate) then
signal sqlstate '45000' set message_text = 'the checkin date must be less than the checkout date!';
end if;
end$$
答案 1 :(得分:0)
CREATE TRIGGER `checkin_enforcement`
BEFORE INSERT ON `booking`
FOR EACH ROW
IF NEW.checkinDate >= NEW.checkoutDate THEN
SIGNAL SQLSTATE '45000' SET MESSAGE_TEXT = 'The check-in date must be before the check-out date!';
END IF
FOR FOR EACH ROW后不需要BEGIN