Question

我有一个资源表和一个resources_votes表，其中每次用户喜欢[vote_id 1]或不喜欢[vote_id 2]资源时我都有一条记录。现在我需要检索从最喜欢的那些订购的所有资源信息到更少的资源信息，并且因为当我使用->with('votes')时资源有许多resources_votes，它返回一个对象数组，每个resources_votes与资源ID相关。

有没有办法可以计算一个资源有多少正投票[vote_id =2]，添加一个包含此计数的字段，并从大多数投票到较少投票的订单排序？

PD：这是一个具有resources_votes关系的资源对象的示例，在那里您可以看到投票数组和投票ID，我需要根据以下内容对其进行统计和排序：

    {
            "id": 2,
            "name": "aspernatur",
            "image": "http://lorempixel.com/480/480/?31738",
            "author": "Max Thiel",
            "created_by": 6,
            "reviewed_by": "Mr. Emiliano Frami",
            "lang_id": 2,
            "resource_type_id": 1,
            "status": "Borrado",
            "resource_type": "Imagen",
            "platforms": [],
            "classifications": [],
            "votes": [
              {
                "id": 2,
                "user_id": 2,
                "resource_id": 2,
                "vote_id": 1
              },
              {
                "id": 29,
                "user_id": 1,
                "resource_id": 2,
                "vote_id": 2
              },
              {
                "id": 24,
                "user_id": 12,
                "resource_id": 2,
                "vote_id": 1
              },
            ]
          },

Answer 1

你可以通过这样的热切加载获得它

votes_count

这将返回名为.data descr byte "This program will check if the PIN is valid with the stated guidelines",0dh,0ah intro byte "-------------------------------------",0dh,0ah byte "Please enter a five digit PIN that validates the guidelines:",0dh,0ah byte "-------------------------------------",0dh,0ah PIN dword ? msg1 byte "PIN is valid",0dh,0ah msg2 byte "PIN is not valid",0dh,0ah .code main PROC mov edx,OFFSET intro ;intro into edx call WriteString ;display intro call Crlf ;new line call ReadInt mov PIN,eax ;get PIN from user call validate invoke ExitProcess,0 main ENDP validate PROC mov si,OFFSET PIN .IF ([esi]>=5) && ([esi]<=9) ;if 1st digit is within 5-9 add esi, TYPE PIN .ELSE mov edx,OFFSET msg2 call WriteString .IF([esi]>=2) && ([esi]<=5) ;if 2nd is within 2-5 add esi, TYPE PIN .ELSE mov edx,OFFSET msg2 call WriteString .IF([esi]>=4) && ([esi]<=8) ;if 3rd is within 4-8 add esi, TYPE PIN .ELSE mov edx,OFFSET msg2 call WriteString .IF([esi]>=1) && ([esi]<=4) ;if 4th is within 1-4 add esi, TYPE PIN .ELSE mov edx,OFFSET msg2 call WriteString .IF([esi]>=3) && ([esi]<=6) ;if 5th is within 3-6 mov edx,OFFSET msg1 call WriteString .ELSE mov edx,OFFSET msg2 call WriteString .ENDIF validate ENDP end main的列。您需要调用该列以显示计数。

Answer 2

您可以使用Eloquent Accessors。

在模型中创建以下自定义字段和功能

protected $appends = ['positiveVotesCounter'];

然后，创建以下函数以检索自定义数据。

function getPositiveVotesCounterAttribute() {
    $totalPositiveVotes = 0;
    foreach($this->votes as $vote) {
        if($vote['id'] == 2) {
            $totalPositiveVotes++;
        }
    }

    return $totalPositiveVotes;
}

更多信息可以在这里找到： https://laravel.com/docs/5.4/eloquent-mutators

祝你好运！

Laravel：通过关系上的count id字段进行排序查询

2 个答案: