我想从数组中选择最大的有效数字

Question

嘿，我正在为作业编写代码而且我被卡住了。我的问题是我想找到满足条件的数组中最大的有效数字，数字在[0,500]之间，可以被5或3整除。这就是我到目前为止所做的：

var numlist =[];
var count = 0 ;
var bignum;


while (count >= 0) { 
    bignum = Number(prompt("Enter Number"));

    if (bignum == 12345){   
        break;
    }

    if (bignum > 500 || bignum < 0){
        document.write("No data to Print");
        continue;
    }

    if (!(bignum % 3 === 0 || bignum % 5 === 0)){
        document.write("No data to Print");
        continue;
    }

    numlist = Math.max(bignum);
    bignum = numlist;

    var loop;

    for (loop = 0; loop <= 10; loop++){
        value = bignum * loop;
        document.write(bignum + " X " + loop + " = " + value + "<br />");
    }
}

这是分配和代码示例

有人能帮助我吗？

Answer 1

在这里，这是一种方法。我试图尽可能地改变它，所以你可以做到这一点＆＃34;你的方式＆＃34;。请稍微研究一下这段代码，然后随意问你是否理解不了解。

＆＃13;

＆＃13;

var numlist = [];
var bignum;

// get the number and populate the array
while (true) { // you don't need a var if you want an infinite loop
    bignum = Number(prompt("Enter Number"));

    if (bignum == 12345) {
        break;
    }

    if (bignum > 500 || bignum < 0) {
        continue;
    }

    if (!(bignum % 3 == 0 || bignum % 5 == 0)) {
        continue;
    }

    numlist.push(bignum); // push method in an array includes a value
}
    
if (numlist.length == 0) {
    document.getElementById('res').innerHTML = "No data to Print";
} else {    
    var max = -Infinity;
    for(var ix = 0; ix<numlist.length; ix++) {
    	if (numlist[ix] > max) max = numlist[ix];
    }
    
    var content = '';
    for (var loop = 0; loop <= 10; loop++) {
        value = max * loop;
        content += max + " X " + loop + " = " + value + "<br />";    
    }
    document.getElementById('res').innerHTML = content;
}

＆＃13;

<div id="res"></div>

＆＃13;

＆＃13;

＆＃13;

这是一个更高级的版本，供您在javascript时学习：:)

＆＃13;

＆＃13;

var numlist = [], bignum;
while ((bignum = Number(prompt("Enter Number"))) != 12345) 
    ((bignum > 0) && (bignum < 500)) && (!(bignum % 3) || !(bignum % 5)) && 
    	numlist.push(bignum);

var max = Math.max(...numlist)
document.getElementById('res').innerHTML = 
    numlist.length && [...Array(11).keys()].reduce((p, _ign, ix)=>
        p += max + " X " + ix + " = " + (max * ix) + "<br />", '') || 'No data to Print';

＆＃13;

<div id="res"></div>

＆＃13;

＆＃13;

＆＃13;