Question

我在JS（Ajax）中编写代码：

function getSportIdAndLeagueId() {

    var action = 'http://localhost:8012/football/football/public/admin/ajax/';
    var teamId = document.getElementById('team_a_id').value;

    var question = "";
    question = new XMLHttpRequest();

    question.onreadystatechange = function() {

        if ( question.readyState == 4 && question.status == 200 ) {
                // document.getElementById('sport_id').innerHTML = question.responseText;
                var allRecord = question.responseText;
                var sport_id = "";
                var league_id = "";

                for (var i = 0; i < allRecord.length; i++) {
                    sport_id = sport_id + allRecord[i];
                    league_id = league_id + allRecord[i];        
                }

                document.getElementById('sport_id').innerHTML = sport_id;
                document.getElementById('league_id').innerHTML = league_id;
        } else {

            document.getElementById('sport_id').innerHTML = 'Error: ' + question.statusText + ' code: ' + question.status + ' readyState: ' + question.readyState;

        }

    }

    question.open("get", action + teamId, true);
    question.send();

}

Ajax在Array中的JSON中返回了我的记录，如下所示：

sport_id:
[{"id":110,"sport_id":1,"league_id":32}]
league_id:
[{"id":110,"sport_id":1,"league_id":32}]

我无法获得sport_id和league_id的数量。我尝试添加此主题enter link description here中的代码：

if(sport_id[i]._type[0]=='sport_id'){
    currentObj = pushNew(sport_id[i].nodeValue);
}

但我已经回复了错误：

statusText：OK状态：200 readyState：3

Answer 1

将此代码用于所需的输出

question.responseType = 'jsonp';

  for (x in sport_id) {
        document.getElementById("sport_id").innerHTML += sport_id[x] + " ";
    }

 for (x in league_id) {
        document.getElementById("league_id").innerHTML += league_id[x] + " ";
    }

Json在数组Javascript和Ajax中

1 个答案: