我有关于热图的问题。我可以通过ggmap可视化热图,并将眼球放在最密集的位置,但我怎样才能得到这些斑点的精确长度和纬度。这是测试代码:
set.seed(1)
mymap <- get_map(location = "Detroit", zoom = 8)
mydata <- data.table(long = runif(min = -84, max = -82.5, n = 100),
lat = runif(min = 42, max = 42.7, n = 100))
g <- ggmap(mymap) +
stat_density2d(data = mydata,
aes(x = long, y = lat, fill = ..level..,alpha = ..level..),
size = 0.5, bins = 10, geom = "polygon") +
scale_alpha_continuous(range(0.1,0.5))
g
答案 0 :(得分:6)
geom_density_2d
的帮助说:
Description:
Perform a 2D kernel density estimation using ‘kde2d’
kde2d
功能位于MASS
包中。
阅读相关文档,您将了解如何从ggplot
正在绘制的核密度中获取值矩阵。
然后将问题简化为找到矩阵的局部最大值:
Given a 2D numeric "height map" matrix in R, how can I find all local maxima?
> library(MASS); library(raster)
> w = matrix(1,3,3)
> x = kde2d(mydata$long, mydata$lat, n=100)
> r = raster(x)
> f <- function(X) max(X, na.rm=TRUE)
> localmax <- focal(r, w, fun = f, pad=TRUE, padValue=NA)
> r2 <- r==localmax
> maxXY <- xyFromCell(r2, Which(r2==1, cells=TRUE))
> image(x,asp=1)
> points(maxXY)
> maxXY
x y
[1,] -82.86796 42.43167
[2,] -83.47583 42.34163
[3,] -82.83831 42.18924