Question

我需要使用bash脚本在 zshrc 文件中添加新插件，为此我搜索包含 plugins =（sometext）

的行

语法

plugin_text=$(grep "^[^#;]" zshrc | grep -n "plugins=(.*)")

直接在终端中运行我得到：

$ grep "^[^;]" zshrc | grep -n "plugins=(.*)"
38:# Example format: plugins=(rails git textmate ruby lighthouse)
40:plugins=(git python pip)

40是正确的行但是当我执行我的bash脚本时，我得到：

$ ./config-minimal
3:plugins=(git python pip)

我需要更改40行插入新插件。例如：

前

plugins=(git python pip)

后

plugins=(git python pip zsh-autosuggestions zsh-syntax-highlighting)

如何通过简单的方式获取此行并替换文本？

我的剧本

function install_zsh {
    # aptitude install zsh
    # sh -c "$(wget https://raw.githubusercontent.com/robbyrussell/oh-my-zsh/master/tools/install.sh -O -)"
    # Install zsh highlighting 
    # cd ~/.oh-my-zsh/custom
    # git clone https://github.com/zsh-users/zsh-syntax-highlighting.git
    # Install zsh auto suggestions
    # git clone git://github.com/zsh-users/zsh-autosuggestions 
    # TODO: Add options in plugins 
    cd ~
    plugin_text=$(grep "^[^#;]" .zshrc | grep -n "plugins=(.*)")
    new_plugins=${plugin_text/)/ zsh-autosuggestions zsh-syntax-highlighting)}
    line_number=${plugin_text/:plugins*/ }
    sed "$(line_number)s/plugin_text/new_plugins/" .zshrc
}

Answer 1

您可以使用简单的sed 's/^plugins=($.*$/plugins=(zsh-autosuggestions zsh-syntax-highlighting \1/' .zshrc：

来处理它

sed 's/\(^plugins=([^)]*\)/\1 zsh-autosuggestions zsh-syntax-highlighting/' .zshrc

或（thx @ 123）：

-i

将function install_zsh { # aptitude install zsh # sh -c "$(wget https://raw.githubusercontent.com/robbyrussell/oh-my-zsh/master/tools/install.sh -O -)" # Install zsh highlighting # cd ~/.oh-my-zsh/custom # git clone https://github.com/zsh-users/zsh-syntax-highlighting.git # Install zsh auto suggestions # git clone git://github.com/zsh-users/zsh-autosuggestions # TODO: Add options in plugins sed -i.bak 's/^plugins=($.*$/plugins=(zsh-autosuggestions zsh-syntax-highlighting \1/' ~/.zshrc }标志添加到infile replacement。

{{1}}

使用bash搜索并替换特定行

1 个答案: