用模板选择右矢量

时间:2017-04-03 13:16:59

标签: c++ templates

我正在关注this question以选择合适的容器,但我遇到了问题。

我有一个selector类必须推回指针向量,但正确的类依赖于它的维度(向量为1,对于矩阵为2):

class selector
{
    struct formValues : std::vector<coolvector<double>*>, std::vector<coolmatrix<double>*> { };

    formValues maps;

public:

    selector() { };

    template<unsigned int formdim, typename F>
    void operator+=(const form<formdim, F> &f)
    {
        typedef typename form<formdim, F>::storage_type storage_type;

        typedef typename std::vector<storage_type*> pointer_type;

        // Push to the right vector
        formValues<pointer_type> &m = maps;

        m.push_back(f.storage.get());
    }        
};

form类具有维度和存储,同样取决于维度,使用共享指针:

template <bool, class if_true, class if_false>
struct type_switch
{
    typedef if_false type;
};

template <class if_true, class if_false>
struct type_switch<true, if_true, if_false>
{
    typedef if_true type;
};

template <class T> class coolvector {};
template <class T> class coolmatrix {};

template<unsigned int formdim, typename F>
class form
{
public:
    form() = delete;

    form(const std::string &s) : type(s)
    {
        storage = std::make_shared<storage_type>();
    }

    std::string type;

    typedef typename type_switch<formdim == 1, coolvector<double>, coolmatrix<double>>::type storage_type;

    std::shared_ptr<storage_type> storage;
};

class oneform : public form<1, oneform>
{
public:
    oneform() = delete;

    oneform(const std::string &s) : form(s) { };

    double operator()(unsigned int i) { return i * 2; };
};

class twoform : public form<2, twoform>
{
public:
    twoform() = delete;

    twoform(const std::string &s) : form(s) { };

    double operator()(unsigned int i, unsigned int j) { return i * 2 + j * 20; };
};

问题在于selector::operator+=我收到此错误:

main.cpp:77:19: error: expected unqualified-id
        formValues<pointer_type> &m = maps;
                  ^

任何提示都表示赞赏!

1 个答案:

答案 0 :(得分:2)

.img0, .img1, .img2, .img3 {position: relative} 不是模板,因此您无法撰写formValues

你的意思是

formValues<pointer_type>

获取pointer_type& m = maps; 的适当基类子对象。