我正在尝试将这个东西(Shannon-Fano算法)从pascal转换为c#:
program ShennonFano;
uses crt;
const
a :array[1..6] of char = ('a','b','c','d','e','f');
af:array[1..6] of integer = (10, 8, 6, 5, 4, 3);
procedure SearchTree(branch:char; full_branch:string; start_pos:integer; end_pos:integer);
var
dS:real;
i, m, S:integer;
c_branch:string;
begin
if (a<>' ') then c_branch := full_branch + branch
else c_branch := '';
if (start_pos = end_pos) then
begin
WriteLn(a[start_pos], ' = ', c_branch);
exit;
end;
dS := 0;
for i:=start_pos to end_pos do dS:= dS + af[i];
dS := dS/2;
S := 0;
i := start_pos;
m := i;
while ((S+af[i]<dS) and (i<end_pos)) do
begin
S := S + af[i];
inc(i); inc(m);
end;
SearchTree('1', c_branch, start_pos, m);
SearchTree('0', c_branch, m+1, end_pos);
end;
begin
WriteLn('Press <enter> to show');
ReadLn;
ClrScr;
SearchTree(' ',' ', 1, 6);
ReadLn;
end;
这是我在c#中的代码:
namespace Shannon_Fano_Alg
{
class Program
{
static char[] a = { 'a', 'b', 'c', 'd', 'e', 'f' };
static int[] af = { 10, 8, 6, 5, 4, 3 };
static bool first = true;
static void Search(char branch, string full_branch, int startPos, int endPos)
{
double dS;
int m, i, S;
string c_branch;
if (first)
{
c_branch = "";
first = false;
}
else
{
c_branch = full_branch + branch;
}
if (startPos == endPos)
{
Console.WriteLine(a[startPos] + " = " + c_branch);
}
dS = 0;
for (i = startPos; i<endPos; i++)
{
dS += af[i];
}
dS /= 2;
S = 0;
i = startPos;
m = i;
while (S + af[i] < dS && i<endPos)
{
S += af[i];
i++;
}
Search('1', c_branch, startPos, m);
Search('0', c_branch, m + 1, endPos);
}
static void Main(string[] args)
{
Program.Search(' ', " ", 0, 5);
Console.ReadKey();
}
}
}
但是,不幸的是我的代码无休止地循环,我得到那样的smth: 这个算法在pascal中运行良好,所以我认为我已经错误地翻译了它。请帮我理解我的错误在哪里。提前谢谢。
答案 0 :(得分:2)
除了BugFinder的回答。
帕斯卡尔有这个:while ((S+af[i]<dS) and (i<end_pos)) do
begin
S := S + af[i];
inc(i); inc(m);
end;
你的C#有这个:
while (S + af[i] < dS && i<endPos)
{
S += af[i];
i++;
}
你不增加m,所以加上m ++;在i ++之后;
答案 1 :(得分:2)
在pascal代码中,你错过了终止&#34;我没有别的事可做&#34;部分
if (start_pos = end_pos) then
begin
WriteLn(a[start_pos], ' = ', c_branch);
exit;
end;
你已经跳过了c#代码中的退出..所以它只是循环
if (startPos == endPos)
{
Console.WriteLine(a[startPos] + " = " + c_branch);
}
您需要在Console.WriteLine之后添加一个返回,例如
if (startPos == endPos)
{
Console.WriteLine(a[startPos] + " = " + c_branch);
return;
}