WHERE语句在左外连接中的位置

Question

在以下查询中，我首先尝试过滤所有network_id = 24的订阅，然后将列payment_plans.plan_type加入ids相同的订阅中。

我认为WHERE语句的定位存在问题，但我不知道它在哪里 - 错误显示连接语句附近存在语法错误

有关错误可能位置的任何建议吗？

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, payment_plans.plan_type
FROM subscriptions WHERE network_id = 24
LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = payment_plans.id


ERROR:  syntax error at or near "LEFT"
LINE 3: LEFT OUTER JOIN payment_plans ON subscription.payment_plan_i...
        ^

Answer 1

SQL语法为select ... from ... join .. on ..where。

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, payment_plans.plan_type
FROM subscriptions 
LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = payment_plans.id
WHERE network_id = 24

这是SQL标准，对所有RDBMS都是一样的。

Answer 2

您的查询应该是：

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, payment_plans.plan_type
FROM subscriptions 
LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = payment_plans.id
WHERE network_id = 24

您可以查看documentation for the SELECT statement, in particular this section。

Answer 3

在join语句后移动你的位置。像这样：

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, 
payment_plans.plan_type
FROM subscriptions 
LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = 
payment_plans.id 
WHERE network_id = 24

Answer 4

你可以试试这个

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, payment_plans.plan_type FROM subscriptions LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = payment_plans.id WHERE subscriptions.network_id = 24