Question

我通过将团队转换为对象将Angular filter group by示例扩展到以下内容。

     var app = angular.module('myApp',['angular.filter']);

app.controller('MainController', ['$scope', function($scope){
  $scope.players = [
  {
    name: 'Gene', 
    team: {
      'id' : '1',
      'name' : 'alpha'
      
    }
  },
  {
    name: 'George', 
    team: {
      'id' : '2',
      'name' : 'beta'
    }
  },
  {
    name: 'Steve', 
    team: {
      'id' : '3',
      'name' : 'gamma'
    }
  },
  {
    name: 'Paula', 
    team: {
      'id' : '2',
      'name' : 'beta'
    }
  },
  {
    name: 'Scruath', 
    team: {
      'id' : '3',
      'name' : 'gamma'
    }
  }
];
}]);

<!DOCTYPE html>
<html>

  <head>
    <script data-require="angularjs@1.6.2" data-semver="1.6.2" src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.2/angular.js"></script>
    <script data-require="angular-filter@*" data-semver="0.5.7" src="//cdnjs.cloudflare.com/ajax/libs/angular-filter/0.5.7/angular-filter.js"></script>
    <link rel="stylesheet" href="style.css" />
    <script src="script.js"></script>
  </head>

  <body ng-app="myApp">
    <div ng-controller="MainController">
      <ul>
        <li ng-repeat="(team, players) in players | groupBy: 'team.name'">
          <a href="#I need the team ID">Group name: {{ team }}</a>
          <ul>
            <li ng-repeat="player in players">
              player: {{ player.name }}
            </li>
          </ul>
        </li>
      </ul>
    </div>
  </body>

</html>

但是，如果我需要团队中的团队ID呢？我该怎么办？

<a href="#I need the team ID">Group name: {{ team }}</a>

我尝试按团队对象进行分组，然后使用team.name和team.id，但它不起作用。另外，我不知道如何使用多个字段(team.id, team.name)

创建一个组

这是working plnkr

Answer 1

我有一个简单的解决方案：

我按team.id分组

<li ng-repeat="(teamid, players) in players | groupBy: 'team.id'">

然后我在组中使用了players[0].team.name

<li ng-repeat="(teamid, players) in players | groupBy: 'team.id'">
    <a href="#Here I can use the group teamid">Group name: {{ players[0].team.name }}</a>
      <ul>
        <li ng-repeat="player in players">
          player: {{ player.name }}
        </li>
     </ul>
</li>

由于每个组中的players只是属于该组的玩家，而且所有人都拥有相同的团队，因此players[0]，players[1]等具有相同的团队名称

＆＃13;

     var app = angular.module('myApp',['angular.filter']);

app.controller('MainController', ['$scope', function($scope){
  $scope.players = [
  {
    name: 'Gene', 
    team: {
      'id' : '1',
      'name' : 'alpha'
      
    }
  },
  {
    name: 'George', 
    team: {
      'id' : '2',
      'name' : 'beta'
    }
  },
  {
    name: 'Steve', 
    team: {
      'id' : '3',
      'name' : 'gamma'
    }
  },
  {
    name: 'Paula', 
    team: {
      'id' : '2',
      'name' : 'beta'
    }
  },
  {
    name: 'Scruath', 
    team: {
      'id' : '3',
      'name' : 'gamma'
    }
  }
];
}]);

＆＃13;

<!DOCTYPE html>
<html>

  <head>
    <script data-require="angularjs@1.6.2" data-semver="1.6.2" src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.2/angular.js"></script>
    <script data-require="angular-filter@*" data-semver="0.5.7" src="//cdnjs.cloudflare.com/ajax/libs/angular-filter/0.5.7/angular-filter.js"></script>
    <link rel="stylesheet" href="style.css" />
    <script src="script.js"></script>
  </head>

  <body ng-app="myApp">
    <div ng-controller="MainController">
      <ul>
        <li ng-repeat="(teamid, players) in players | groupBy: 'team.id'">
          <a href="#Here I can use the group teamid">Group name: {{ players[0].team.name }}</a>
          <ul>
            <li ng-repeat="player in players">
              player: {{ player.name }}
            </li>
          </ul>
        </li>
      </ul>
    </div>
  </body>

</html>

＆＃13;

Answer 2

您应该按team.id分组，因为团队名称不是唯一的。这样可以避免错误的数据输出。好吧好吧。我能够通过在控制器中预先收集您的团队并通过team.id在单独的对象中对其进行规范化来解决您的问题 - demo fiddle：

视图

<body ng-app="myApp">
<div ng-controller="MainController">
    <ul>
        <li ng-repeat="(team, players) in players | groupBy: 'team.id'">
            <a href="{{ team }} ">Group name: {{ teams[team].name }}</a>
            <ul>
                <li ng-repeat="player in players">
                    player: {{ player.name }}
                </li>
            </ul>
        </li>
    </ul>
</div>
</body>

AngularJS应用程序

var app = angular.module('myApp',['angular.filter']);

app.controller('MainController', ['$scope', function($scope){

    $scope.players = [
        {
            name: 'Gene',
            team: {
                'id' : '1',
                'name' : 'alpha'

            }
        }, {
            name: 'George',
            team: {
                'id' : '2',
                'name' : 'beta'
            }
        }, {
            name: 'Steve',
            team: {
                'id' : '3',
                'name' : 'gamma'
            }
        }, {
            name: 'Paula',
            team: {
                'id' : '4',
                'name' : 'beta'
            }
        }, {
            name: 'Scruath',
            team: {
                'id' : '5',
                'name' : 'gamma'
            }
        }];

    $scope.teams = {};

    $scope.players.forEach(function (player) {
        if (angular.isUndefined($scope.teams[player.team.id])) {
            $scope.teams[player.team.id] = player.team;
        }
    });
}]);

角度过滤器 - 按对象（或多个字段）分组

2 个答案:

视图

AngularJS应用程序