Question

我有％arch的问题：~1,3％正确显示回显％arch：~1,3％输出x64就像它应该的那样但是当它被用作一个变量时，它会把一切搞得一团糟

@echo off
setlocal enabledelayedexpansion
Color 0A
cls
title PORTABLE LASTPASS LAUNCHER

:ARCHCHECK
cls
set arch=
if exist "%PROGRAMFILES(X86)%" set "arch=_x64" & goto LASTPASSCHECK

:LASTPASSCHECK
cls
if not exist .\bin\lastpass\lastapp%arch%.exe goto FILECHECK
if not exist .\bin\lastpass\lastapphook%arch%.dll goto FILECHECK
goto WGETUPDATE

:FILECHECK
cls
if not exist .\extra\lastappinstall%arch%.exe goto DOWNLOADLASTPASS
if not exist .\bin\7-ZipPortable\7-ZipPortable.exe goto 7ZIPINSTALLERCHECK
.\bin\7-ZipPortable\App\7-Zip%arch:~1,3%\7z.exe e .\extra\lastappinstall%arch%.exe lastapp%arch%.exe -o.\bin\lastpass\
.\bin\7-ZipPortable\App\7-Zip%arch:~1,3%\7z.exe e .\extra\lastappinstall%arch%.exe lastapphook%arch%.dll -o.\bin\lastpass\
goto LASTPASSCHECK

:DOWNLOADLASTPASS
cls
if exist lastappinstall%arch%.exe goto MOVELASTPASS
if not exist .\bin\wget.exe call :DOWNLOADWGET
.\bin\wget.exe https://lastpass.com/download/cdn/lastappinstall%arch%.exe

:MOVELASTPASS
cls
move lastappinstall%arch%.exe .\extra\lastappinstall%arch%.exe
goto FILECHECK

当我用作变量时得到的输出是它认为它以某种方式说“ziparcharcharch”：/

Answer 1

自己解决了而不是％arch：~1,3％我应该把％arch：~2,2％，因为我想要两个跳到字符并打印下一个2 即，而不是_x64变成x64，它变成64

需要有关批处理变量和子字符串的帮助

1 个答案: