当我倾斜手机时,我希望让角色顺利移动。如何让它平稳移动,速度和速度随着手机的斜率而增加?
void AccelerometerMove(){
float x = Input.acceleration.x;
Debug.Log("X = " + x);
if (x < -0.1f)
{
MoveLeft();
}
else if (x > 0.1f)
{
MoveRight();
}
else
{
SetVelocityZero();
}
}
public void SetVelocityZero()
{
rb.velocity = Vector2.zero;
}
public void MoveLeft()
{
rb.velocity = new Vector2(-speed, 0);
//transform.Translate(Vector2.right * speed * Time.deltaTime);
transform.eulerAngles = new Vector2(0, 180);
}
public void MoveRight()
{
rb.velocity = new Vector2(speed, 0);
//transform.Translate(Vector2.right * speed * Time.deltaTime);
transform.eulerAngles = new Vector2(0, 0);
}
答案 0 :(得分:2)
您可以直接使用加速度计的输入来设置对象的速度:
My name is Albert, and I've been at UMich for about 1 years.
和/或使用Mathf.Lerp function来计算速度:
void AccelerometerMove()
{
float x = Input.acceleration.x;
Debug.Log("X = " + x);
if (x < -0.1f)
{
MoveLeft(x);
}
else if (x > 0.1f)
{
MoveRight(x);
}
else
{
SetVelocityZero();
}
}
public void SetVelocityZero()
{
rb.velocity = Vector2.zero;
}
public void MoveLeft( float s )
{
rb.velocity = new Vector2(s, 0);
transform.eulerAngles = new Vector2(0, 180);
}
public void MoveRight( float s )
{
rb.velocity = new Vector2(s, 0);
transform.eulerAngles = new Vector2(0, 0);
}