Question

我有一点问题..我想做车注册，我想拥有（指向一个Person对象的指针），但是当我想带有获取功能的拥有者时，我无法做到这一点。这对我来说是个谜......也许我在某个地方犯了一个小错误，我找不到它..请帮忙:)

class Person
{
    friend class Cars;
public:
    Person(){}
    Person(uint8_t age, string name) :m_age(age), m_name(name)
    {
        m_idGener = s_idGenerator++;
    }

    int getId()
    {
        return m_idGener;
     }
    uint8_t getAge()
    {
        return m_age;
    }
    string getName()
    {
     return m_name;
    }
 private:
    string m_name;
    uint8_t m_age;
    static int s_idGenerator;
    int m_idGener;

 };
 class Cars:public Person
 {

 public:
     Person *m_owner; // this is my pointer which i want to point to cars     Object 
  it will stay public for the test after the test i will move it in the     private section 
    Cars()
    {
    }
   // getters and setters 

    Cars setOwner(Cars &object, Person &owner) // with this function i set the owner 
    {
      object.m_owner = &owner;
    }
    Cars getOwner(Cars &object) /// here is my problem i can't take the owner 
    {
       return *(object.m_owner); // but i can't take the owner 
    }

     uint16_t getHorsePower()
    {
       return horsePower;
    }
     string getRegNumber()
    {
       return registrationNumber;
    }
  private:
     string m_manufacturerName;
     string modelName;
     uint16_t horsePower;
    string registrationNumber;

};

int Person::s_idGenerator = 0;

Answer 1

你犯了更多错误。至少应该纠正以下几点：

Cars setOwner(Cars &object,  .....

此方法不会返回值，因此它应该是无效的。 car对象应该是调用方法的对象，而不是参数。

Cars getOwner(Cars &object) /// here is my problem i can't take the owner 
{
   return *(object.m_owner); // but i can't take the owner 
}

在这个方法中，我会将返回类型更改为Person *，然后返回m_owner。不需要参数。

修改后的工作示例：

#include <string>
#include <iostream>
using namespace std;
class Person
{
    friend class Cars;
public:
    Person(){}
    Person(uint8_t age, string name) :m_age(age), m_name(name)
    {
        m_idGener = s_idGenerator++;
    }

    int getId()
    {
        return m_idGener;
     }
    uint8_t getAge()
    {
        return m_age;
    }
    string getName()
    {
     return m_name;
    }
 private:
    string m_name;
    uint8_t m_age;
    static int s_idGenerator;
    int m_idGener;

 };
 class Cars:public Person
 {

 public:
     Person *m_owner; // this is my pointer which i want to point to cars     Object 
                      // it will stay public for the test after the test i will move it in the     private section 
    Cars()
    {
    }
   // getters and setters 

    void setOwner(Person &owner) // with this function i set the owner 
    {
      m_owner = &owner;
    }
    Person *getOwner() /// here is my problem i can't take the owner 
    {
       return (m_owner); // but i can't take the owner 
    }

     uint16_t getHorsePower()
    {
       return horsePower;
    }
     string getRegNumber()
    {
       return registrationNumber;
    }
  private:
     string m_manufacturerName;
     string modelName;
     uint16_t horsePower;
    string registrationNumber;

};

int Person::s_idGenerator = 0;

int main() {
  Person p(5,"Bill");
  Cars c;

  c.setOwner(p);
  cout << c.getOwner()->getName();
}

Answer 2

下面：

Cars setOwner(Cars &object, Person &owner) // with this function i set the owner
{ 
object.m_owner = &owner;
}

您将值类型声明为“汽车”，但您不会返回任何内容。

在这里：

Cars getOwner(Cars &object) /// here is my problem i can't take the owner
{ 
return *(object.m_owner); // but i can't take the owner 
}

您想要返回“Person”对象，但是您再次将值类型声明为“Cars”。

所以你可以改变这样的功能：

首先：

void setOwner(Cars &object, Person &owner);

第二

Person getOwner(Cars &object);

指针另一个对象

2 个答案: