我有一个字符串
Subtracting polynomials:
Term 1: 2x^3 + 1x^2 + 4x - 9
Term 2: 2x^3 + 1x^2 + 4x - 9
Difference: 0
Term 1: 2x^3 + 1x^2 + 4x - 9
Term 2: 3x^2 - 4x + 8
Difference: 2x^3 - 2x^2 + 8x - 17
Term 1: 2x^3 + 1x^2 + 4x - 9
Term 2: -4x^2 + 5x + 3
Difference: 2x^3 + 5x^2 - 1x - 12
Term 1: 2x^3 + 1x^2 + 4x - 9
Term 2: 5x^4 - 5
Difference: -5x^4 + 2x^3 + 1x^2 + 4x - 4
Term 1: 2x^3 + 1x^2 + 4x - 9
Term 2: 2x^3 - 8x^2 + 4x
Difference: + 9x^2 - 9
Term 1: 3x^2 - 4x + 8
Term 2: 2x^3 + 1x^2 + 4x - 9
Difference: -2x^3 + 2x^2 - 8x + 17
Term 1: 3x^2 - 4x + 8
Term 2: 3x^2 - 4x + 8
Difference: 0
Term 1: 3x^2 - 4x + 8
Term 2: -4x^2 + 5x + 3
Difference: 7x^2 - 9x + 5
Term 1: 3x^2 - 4x + 8
Term 2: 5x^4 - 5
Difference: -5x^4 + 3x^2 - 4x + 13
Term 1: 3x^2 - 4x + 8
Term 2: 2x^3 - 8x^2 + 4x
Difference: -2x^3 + 11x^2 - 8x + 8
Term 1: -4x^2 + 5x + 3
Term 2: 2x^3 + 1x^2 + 4x - 9
Difference: -2x^3 - 5x^2 + 1x + 12
Term 1: -4x^2 + 5x + 3
Term 2: 3x^2 - 4x + 8
Difference: -7x^2 + 9x - 5
Term 1: -4x^2 + 5x + 3
Term 2: -4x^2 + 5x + 3
Difference: 0
Term 1: -4x^2 + 5x + 3
Term 2: 5x^4 - 5
Difference: -5x^4 - 4x^2 + 5x + 8
Term 1: -4x^2 + 5x + 3
Term 2: 2x^3 - 8x^2 + 4x
Difference: -2x^3 + 4x^2 + 1x + 3
Term 1: 5x^4 - 5
Term 2: 2x^3 + 1x^2 + 4x - 9
Difference: 5x^4 - 2x^3 - 1x^2 - 4x + 4
Term 1: 5x^4 - 5
Term 2: 3x^2 - 4x + 8
Difference: 5x^4 - 3x^2 + 4x - 13
Term 1: 5x^4 - 5
Term 2: -4x^2 + 5x + 3
Difference: 5x^4 + 4x^2 - 5x - 8
Term 1: 5x^4 - 5
Term 2: 5x^4 - 5
Difference: 0
Term 1: 5x^4 - 5
Term 2: 2x^3 - 8x^2 + 4x
Difference: 5x^4 - 2x^3 + 8x^2 - 4x - 5
Term 1: 2x^3 - 8x^2 + 4x
Term 2: 2x^3 + 1x^2 + 4x - 9
Difference: - 9x^2 + 9
Term 1: 2x^3 - 8x^2 + 4x
Term 2: 3x^2 - 4x + 8
Difference: 2x^3 - 11x^2 + 8x - 8
Term 1: 2x^3 - 8x^2 + 4x
Term 2: -4x^2 + 5x + 3
Difference: 2x^3 - 4x^2 - 1x - 3
Term 1: 2x^3 - 8x^2 + 4x
Term 2: 5x^4 - 5
Difference: -5x^4 + 2x^3 - 8x^2 + 4x + 5
Term 1: 2x^3 - 8x^2 + 4x
Term 2: 2x^3 - 8x^2 + 4x
Difference: 0
我想将其更改为
<sec:authorize ifAnyGranted="ROLE_BAR,ROLE_FOO,ROLE_USER">
请注意，角色数量可以从一个到几个。
我可以使用 <sec:authorize access="hasAnyRole('ROLE_BAR','ROLE_FOO','ROLE_USER')">
搜索是否只有一个角色，例如<sec:authorize\s+ifAnyGranted="(\w+)"\s*>。
当然，如果有两个，我可以将其写为<sec:authorize ifAnyGranted="ROLE_USER">并使用<sec:authorize\s+ifAnyGranted="(\w+),(\w+)"\s*>替换找到的字符串。
但是如何在一条迹线中替换所有这些模式？有可能吗？