Question

我正在尝试将XML节点的内容绑定到下拉列表，但没有太大成功。

最初，整个XML文档绑定到转发器 - 这很好用，但是现在我需要根据“”节点中的子节点显示一个下拉列表，但是我得到了数据在根级别无效。第1行，dropDownList上DataBind（）方法的第1位错误消息。

有人能告诉我，我做错了吗？

我正在使用的代码片段是：

    IXPathNavigable x = (IXPathNavigable)e.Item.DataItem;
    XPathNavigator questionNode = x.CreateNavigator();
   string question = questionNode.SelectSingleNode("questionText").ToString();

   //string title = xePage.SelectSingleNode("q").InnerText;

    Literal questionText = (Literal)e.Item.FindControl("litQuestionText");
    questionText.Text = question;
    Panel iconDiv = (Panel)e.Item.FindControl("divIcon");
    iconDiv.CssClass = string.Format("icon {0}", questionNode.SelectSingleNode("iconType"));
    Panel sliderPanel = (Panel)e.Item.FindControl("pnlSlider");
    DropDownList answerDropDown = (DropDownList)e.Item.FindControl("ddlAnswer");
    TextBox answerText = (TextBox)e.Item.FindControl("txtAnswer");

    switch (questionNode.SelectSingleNode("answerType").ToString())
    {
        case "d": 
            sliderPanel.Visible = false;
            answerText.Visible = false;
            answerDropDown.Visible = true;

            XmlDataSource answersList = new XmlDataSource();
            answersList.Data = questionNode.Select("answers").ToString();
            Response.Write(answersList.ToString());
            //XPathNodeIterator answers = questionNode.Select("answers");
            //answers.AsQueryable();
            answersList.ID = questionNode.SelectSingleNode("questionId").ToString();
            answerDropDown.DataSource = answersList;
            answerDropDown.DataTextField = "@display";
            answerDropDown.DataValueField = "@value";
            answerDropDown.DataBind();
            break;

        case "s":
            sliderPanel.Visible = true;
            answerText.Visible = false;
            answerDropDown.Visible = false;
            break;
        case "t":
            sliderPanel.Visible = false;
            answerText.Visible = true;
            answerDropDown.Visible = false;
            break;

我正在使用的XML是：

<questions>
  <question>
    <questionId>1</questionId>
    <questionText>Question here?</questionText>
    <iconType>a</iconType>
    <answerType>d</answerType>
    <answers>
      <answer value="-3" display="Extremely badly"/>
      <answer value="-2" display="Very badly"/>
      <answer value="-1" display="Quite badly"/>
      <answer value="0" display="Neither well nor badly"/>
      <answer value="1" display="Quite well"/>
      <answer value="2" display="Very well"/>
      <answer value="3" display="Extremely well"/>
    </answers>
  </question>
  <question>
    <questionId>1</questionId>
    <questionText>Question again here?</questionText>
    <iconType>b</iconType>
    <answerType>s</answerType>
    <answers/>
  </question>
</questions>

Answer 1

显然我错过了xml文档顶部的xml声明。聪明。

但是，实现此功能的最佳方法是为问题和答案创建问卷调查对象和类，然后通过反序列化将XML转换为类。然后，您可以将调查问卷的问题绑定到下拉列表中，在完成创建对象所需的初始工作后，它基本上可以更好，更轻松地完成工作。

将xml节点的子节点绑定到ASP.Net DropDownList

1 个答案: