将自定义系统调用添加到内核时出错

Question

所以我一直在将自定义系统调用添加到内核中。这是我的系统调用的源代码：

//sys_procmem.c. This syscall helps users to show the memory layout of a specific process.
#include <linux/linkage.h>
#include <linux/sched.h>
struct proc_segs {
    unsigned long my_id;
    unsigned long start_code;
    unsigned long end_code;
    unsigned long start_data;
    unsigned long end_data;
    unsigned long start_heap;
    unsigned long end_heap;
    unsigned long start_stack;
};
asmlinkage long sys_procmem( int pid, struct proc_segs * info) {
    struct task_struct *task;
    info->my_id = 1512853;
    for_each_process(task){
        if((int) task->pid==pid){
                info->start_code=task->mm->start_code;
                info->end_code=task->mm->end_code;
                info->start_data=task->mm->start_data;
                info->end_data=task->mm->end_data;
                info->start_heap=task->mm->start_brk;
                info->end_heap=task->mm->brk;
                info->start_stack=task->mm->start_stack;
                return 0;
        }
    }
    return -1;
}

在我编译内核之后编写测试程序时，一切似乎都很好，源代码：

//sys.c
#include <sys/syscall.h>
#include <stdio.h>
#include <unistd.h>
#define SIZE 100
int main() {
      long sysvalue;
      unsigned long info[SIZE];
      sysvalue = syscall([number_32], 1, info)
      printf("My ID: %lu\n", info[0]);
}

我用以下程序编译了程序：

gcc sys.c -o sys

然后我用：

运行它

./sys

我收到了这个错误：

请帮助我，谢谢你们阅读：）