使用HttpURLConnection将HTTP数据从HTTP Java客户端发送到servlet时出现问题

时间:2010-11-30 16:06:42

标签: java servlets character-encoding

我有独立的java客户端使用httpURLconnection类将xml数据发送到http servlet。但是数据以不可打印的字符格式显示。

对于模拟,我一直在尝试发送简单的字符串,但它仍然以不可打印的格式出现。

我编写了以下客户端代码来与servlet进行通信,

import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.net.HttpURLConnection;
import java.net.ProtocolException;
import java.net.URL;

public class HttpClient implements IClient {

    private static IClient client = null;

    private HttpURLConnection httpConn = null;

    private OutputStream output = null;

    private InputStream input = null;

    private OutputStreamWriter out = null;

    private HttpClient() {
    }

    public static IClient getHttpClient() {
        if (client == null) {
            client = new HttpClient();
        }
        return client;
    }

    @Override
    public void connect(String urlString) throws IOException {
        URL url = new URL(urlString);
        httpConn = (HttpURLConnection) url.openConnection();
        initConnection();
        httpConn.connect();
        output = httpConn.getOutputStream();
        input = httpConn.getInputStream();
        System.out.println("Connection Response:" + httpConn.getResponseCode());
    }

    @Override
    public void sendFile(File file) throws IOException {
        // BufferedOutputStream bos = new BufferedOutputStream(output);
        // InputStream fis = new FileInputStream(file);
        // int bytesRead = 0;
        // byte[] buffer = new byte[8192];
        // while ((bytesRead = fis.read(buffer, 0, 8192)) != -1) {
        // bos.write(buffer, 0, bytesRead);
        // System.out.println("write:"+buffer);
        // }
        // bos.close();
        // fis.close();

        OutputStreamWriter out = new OutputStreamWriter(output, "UTF-16");
        out.write("test me");
    }

    @Override
    public boolean isConnected() {
        return httpConn != null ? true : false;
    }

    @Override
    public void close() {
        httpConn.disconnect();
    }

    private void initConnection() throws ProtocolException {
        httpConn.setDoOutput(true);
        httpConn.setDoInput(true);
        httpConn.setRequestMethod("POST");
        httpConn.setUseCaches(false);
        httpConn.setRequestProperty("Content-Type",
                "text/xml; charset=\"UTF-16\"");
        httpConn.setRequestProperty("Connection", "Keep-Alive");

    }

    private static byte[] getBytesFromFile(File file) throws IOException {

        InputStream is = new FileInputStream(file);
        System.out.println("\nDEBUG: FileInputStream is " + file);

        // Get the size of the file
        long length = file.length();
        System.out.println("DEBUG: Length of " + file + " is " + length + "\n");

        /*
         * You cannot create an array using a long type. It needs to be an int
         * type. Before converting to an int type, check to ensure that file is
         * not loarger than Integer.MAX_VALUE;
         */
        if (length > Integer.MAX_VALUE) {
            System.out.println("File is too large to process");
            return null;
        }

        // Create the byte array to hold the data
        byte[] bytes = new byte[(int) length];

        // Read in the bytes
        int offset = 0;
        int numRead = 0;
        while ((offset < bytes.length)
                && ((numRead = is.read(bytes, offset, bytes.length - offset)) >= 0)) {

            offset += numRead;

        }

        // Ensure all the bytes have been read in
        if (offset < bytes.length) {
            throw new IOException("Could not completely read file "
                    + file.getName());
        }

        return bytes;

    }

}

和servlet代码如下,

import java.io.BufferedInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class XMLServlet extends HttpServlet {

    @Override
    protected void doGet(HttpServletRequest req, HttpServletResponse resp)
            throws ServletException, IOException {
        doPost(req, resp);
    }

    protected void doPost(HttpServletRequest req, HttpServletResponse resp)
            throws ServletException, IOException {
        System.out.println("=========inside doPost=========");
//      BufferedInputStream bis = new BufferedInputStream(req.getInputStream());
//      OutputStream fos = new FileOutputStream("test.xml");
//      int bytesRead = 0;
//      byte[] buffer = new byte[8192];
//      while ((bytesRead = bis.read(buffer, 0, 8192)) != -1) {
//          System.out.println("read:"+buffer);
//          fos.write(buffer, 0, bytesRead);
//      }
//      fos.close();
//      bis.close();
//      

        req.setCharacterEncoding("UTF-16");
        InputStreamReader isr = new InputStreamReader(req.getInputStream(),"UTF-16");
        char[] data = new char[10];
        isr.read(data);
        System.out.println(data);
        for (char c : data) {
            System.out.println(c);
        }
    }

}

请帮助我摆脱这个问题。

3 个答案:

答案 0 :(得分:2)

我认为你过于复杂了。我只是写了类似的东西,它接受任何文件并通过HTTP将它传递给servlet。请记住:所有数据都是二进制(包括文本文件) - 句点。由给定的应用程序来解释该二进制数据。例如,notepad.exe只读取一组二进制数据并尝试使用ASCII标准对其进行格式化。因此,知道这一点,只需使用原始流读取文件,将连接的mime类型设置为application / octet-stream并通过“PUT”方法发送。 servlet代码应该使用请求中的原始InputStream读取文件,并在其空间中创建相应的文件。

从客户端代码:

URL url = new URL(urlString);
HttpURLConnection cnx = (HttpURLConnection)url.openConnection();
cnx.setRequestMethod("PUT");
cnx.setRequestProperty("Content-Type", "application/octet-stream");
// optional request property
cnx.setRequestProperty("filename", filename);
cnx.setDoOutput(true);
cnx.connect();
BufferedInputStream fileIn = 
       new BufferedInputStream(new FileInputStream(fileName), BUFFER_SIZE);
BufferedOutputStream out = 
       new BufferedOutputStream(cnx.getOutputStream(), BUFFER_SIZE);
byte[] bytes = new byte[BUFFER_SIZE];
int bytesRead;
while((bytesRead = fileIn.read(bytes)) != -1){
   out.write(bytes, 0, bytesRead);
}

就是这样。

现在是servlet代码....

public void doPut(HttpServletRequest request, HttpServletResponse response){
    String filename = (String)request.getHeader("filename");
    StringBuilder fullPath = new StringBuilder(100);
    ServletContext ctxt = getServletContext();
    fullPath.append(ctxt.getRealPath(""))
      .append("uploads\\").append(filename);
    File f = new File(fullPath.toString());
    f.createNewFile();
    InputStream in = request.getInputStream();
    BufferedOutputStream fileOut = 
        new BufferedOutputStream(new FileOutputStream(f));
    byte[] bytes = new byte[BUFFER_SIZE];
    int bytesRead;
    while((bytesRead = in.read(bytes)) != -1){
       fileOut.write(bytes, 0, bytesRead);
    }
    fileOut.flush();
    fileOut.close();
    response.setStatus(HttpServletResponse.SC_CREATED);   
}

答案 1 :(得分:1)

使用http方法将文件上传到服务器有两种主要方法:

  1. 使用PUT方法上传文件。这允许您一次将一个文件放到服务器上。 PUT方法易于实现,但您无法使用PUT方法从html表单上传文件(例如,在网络浏览器中上传表单)。

  2. 使用POST方法上传文件。这更复杂,但大多数网站使用此文件将文件上传到服务器。您可以根据请求进行多个文件上传。这就是我要谈的内容。

  3. 注意:除非您以某种方式对其进行编码,否则GET不会用于文件上传。

    使用URLConnection上传文件不是直截了当的,需要您在“multipart form”中准备数据。当然,你不应该自己做。有许多库可以为您处理此问题,例如: HttpClient。如果你真的想使用URLConnection,我会参考之前关于“How to use java.net.URLConnection to fire and handle HTTP requests”的问题

    以下是使用HttpClient上传文件的代码。它是从HttpClient示例代码中简化而来的。

    import java.io.File;
    
    
    import org.apache.commons.httpclient.HttpClient;
    import org.apache.commons.httpclient.HttpStatus;
    import org.apache.commons.httpclient.methods.PostMethod;
    import org.apache.commons.httpclient.methods.multipart.FilePart;
    import org.apache.commons.httpclient.methods.multipart.MultipartRequestEntity;
    import org.apache.commons.httpclient.methods.multipart.Part;
    import org.apache.commons.httpclient.params.HttpMethodParams;
    
    public class MultipartFileUploadApp {
    
        public static void main(String[] args) {
            String targetURL = "http://localhost:8080/yourserver/upload";
            File targetFile = new File("/path/to/your/file.txt");
    
            PostMethod filePost = new PostMethod(targetURL);
    
            filePost.getParams().setBooleanParameter(HttpMethodParams.USE_EXPECT_CONTINUE, false);
    
            try {
    
                System.out.println("Uploading " + targetFile.getName() + " to " + targetURL);
    
                // add more parts you want to upload multiple files.
                Part[] parts = {new FilePart(targetFile.getName(), targetFile)};
    
                filePost.setRequestEntity(new MultipartRequestEntity(parts, filePost.getParams()));
    
                HttpClient client = new HttpClient();
                client.getHttpConnectionManager().getParams().setConnectionTimeout(5000);
    
                int status = client.executeMethod(filePost);
    
                if (status == HttpStatus.SC_OK) {
                    System.out.println("Upload complete, response=" + filePost.getResponseBodyAsString());
                } else {
                    System.out.println("Upload failed, response=" + HttpStatus.getStatusText(status));
                }
            } catch (Exception ex) {
                System.out.println("Error: " + ex.getMessage());
                ex.printStackTrace();
            } finally {
                filePost.releaseConnection();
            }
    
    
        }
    }
    

    对于服务器端,您必须解析多部分表单请求。当然,有一些库可以帮到你。这是我正在使用的snipplet

    import java.io.File;
    import java.io.IOException;
    import java.io.PrintWriter;
    import java.util.Iterator;
    import java.util.List;
    
    import javax.servlet.ServletConfig;
    import javax.servlet.ServletException;
    import javax.servlet.http.HttpServlet;
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;
    
    import org.apache.commons.fileupload.FileItem;
    import org.apache.commons.fileupload.FileUploadException;
    import org.apache.commons.fileupload.disk.DiskFileItemFactory;
    import org.apache.commons.fileupload.servlet.ServletFileUpload;
    
    public class CommonsFileUploadServlet extends HttpServlet {
    
        private static final String TMP_DIR_PATH = "c:\\tmp";
        private File tmpDir;
        private static final String DESTINATION_DIR_PATH = "c:\\tmp\\files";
        private File destinationDir;
    
        public void init(ServletConfig config) throws ServletException {
            super.init(config);
            tmpDir = new File(TMP_DIR_PATH);
            if (!tmpDir.isDirectory()) {
                throw new ServletException(TMP_DIR_PATH + " is not a directory");
            }
            //String realPath = getServletContext().getRealPath(DESTINATION_DIR_PATH);
            destinationDir = new File(DESTINATION_DIR_PATH);
            if (!destinationDir.isDirectory()) {
                throw new ServletException(DESTINATION_DIR_PATH + " is not a directory");
            }
    
        }
    
        protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
            PrintWriter out = response.getWriter();
            response.setContentType("text/plain");
            out.println("<h1>Servlet File Upload Example using Commons File Upload</h1>");
            out.println();
    
            DiskFileItemFactory fileItemFactory = new DiskFileItemFactory();
            /*
             *Set the size threshold, above which content will be stored on disk.
             */
            fileItemFactory.setSizeThreshold(1 * 1024 * 1024); //1 MB
            /*
             * Set the temporary directory to store the uploaded files of size above threshold.
             */
            fileItemFactory.setRepository(tmpDir);
    
            ServletFileUpload uploadHandler = new ServletFileUpload(fileItemFactory);
            try {
                /*
                 * Parse the request
                 */
                List items = uploadHandler.parseRequest(request);
                out.println("Count : " + items.size());
                Iterator itr = items.iterator();
                while (itr.hasNext()) {
                    FileItem item = (FileItem) itr.next();
                    /*
                     * Handle Form Fields.
                     */
                    if (item.isFormField()) {
                        out.println("Field = " + item.getFieldName() + ", Value = " + item.getString());
                    } else {
                        //Handle Uploaded files.
                        out.println("Field Name = " + item.getFieldName()
                                + ", File Name = " + item.getName()
                                + ", Content type = " + item.getContentType()
                                + ", File Size = " + item.getSize());
                        /*
                         * Write file to the ultimate location.
                         */
                        File file = new File(destinationDir, item.getName());
                        item.write(file);
                    }
                }
                out.close();
            } catch (FileUploadException ex) {
                log("Error encountered while parsing the request", ex);
            } catch (Exception ex) {
                log("Error encountered while uploading file", ex);
            }
    
        }
    }
    

答案 2 :(得分:0)

  

我有独立的java客户端使用httpURLconnection类将xml数据发送到http servlet。但是数据以不可打印的字符格式显示。

我能理解。您将数据作为UTF-16发送,但XML文件本身可能不会以UTF-16保存。您需要使用与保存的XML文件相同的字符编码。这通常是UTF-8。

  

对于模拟,我一直在尝试发送简单的字符串,但它仍然以不可打印的格式出现。

我不明白。它应该像在代码中那样正常工作。可能你没有正确测试它。