尝试播种表时,它会显示一个数组到字符串转换'错误。
这是错误的输出:
[Illuminate\Database\QueryException]
Array to string conversion (SQL: insert into `reviews` (`user_id`, `name`, `location`, `header`, `comments`, `identifier`, `stars`, `privacy`, `actioned`, `appr
oved`, `created_at`) values (10, Bradley Davis, Paulastad, Commodi quas expedita eum., Voluptas magni iusto nemo ea vitae harum quasi., 6c621319-c6ba-41c1-bb0b-696b602470
ef, 5, 1, 0, 1, 2017-03-25 11:44:12))
表格结构:
Schema::create('reviews', function (Blueprint $table) {
$table->increments('id');
$table->integer('user_id');
$table->string('name')->nullable();
$table->string('location')->nullable();
$table->string('header')->nullable();
$table->string('comments')->nullable();
$table->uuid('identifier');
$table->integer('stars')->nullable();
$table->boolean('privacy')->default('1');
$table->boolean('actioned')->default('0');
$table->boolean('approved')->default('0');
$table->nullableTimestamps();
});
种子功能:
for ($i = 1; $i < 41; $i++) {
$name = User::where('id', $i + 9)->pluck('name')->all();
$uuid = Uuid::generate(4);
$review = [
'user_id' => $i + 9,
'name' => $name,
'location' => $faker->city,
'header' => $faker->sentence($nbWords = 3, $variableNbWords = true),
'comments' => $faker->text($maxNbChars = 50),
'identifier' => $uuid,
'stars' => [1, 2, 3, 4, 5][rand(0, count([1, 2, 3, 4, 5]) - 1)],
'privacy' => [1, 0][rand(0, count([1, 0]) - 1)],
'actioned' => [1, 0][rand(0, count([1, 0]) - 1)],
'approved' => [0, 1][rand(0, count([0, 1]) - 1)],
'created_at' => Carbon::now()->subWeeks(array_rand([2, 3, 4, 5, 6, 7], 1))
];
}
DB::table('reviews')->insert($review);
的print_r($审查):
Array
(
[user_id] => 10
[name] => Array
(
[0] => David Robertson
)
[location] => Lake Suzannechester
[header] => Repellendus aut alias exercitationem.
[comments] => Sunt non temporibus pariatur totam aut qui.
[identifier] => Webpatser\Uuid\Uuid Object
(
[bytes:protected] => �a�?�IB��"�mLC�
[hex:protected] =>
[string:protected] => d51961bb-3fcf-4942-a0d9-22a56d4c4392
[urn:protected] =>
[version:protected] =>
[variant:protected] =>
[node:protected] =>
[time:protected] =>
)
[stars] => 4
[privacy] => 1
[actioned] => 1
[approved] => 1
[created_at] => Carbon\Carbon Object
(
[date] => 2017-03-04 12:04:01.225487
[timezone_type] => 3
[timezone] => UTC
)
)
答案 0 :(得分:1)
如您所见,此处存在多个问题,例如$name
不包含名称,但它包含数组,您应该使用:
$name = User::find($i + 9)->name;
代替。
类似于$uuid
- 它应该返回字符串而不是某个对象。
当我看这一部分时:
'stars' => [1, 2, 3, 4, 5][rand(0, count([1, 2, 3, 4, 5]) - 1)],
'privacy' => [1, 0][rand(0, count([1, 0]) - 1)],
'actioned' => [1, 0][rand(0, count([1, 0]) - 1)],
'approved' => [0, 1][rand(0, count([0, 1]) - 1)],
'created_at' => Carbon::now()->subWeeks(array_rand([2, 3, 4, 5, 6, 7], 1))
太复杂了。
你可以在这里使用这样的东西:
'stars' => rand(1, 5),
'privacy' => rand(0, 1),
'actioned' => rand(0, 1),
'approved' => rand(0, 1),
'created_at' => Carbon::now()->subWeeks(rand(2, 7))->toDateTimeString(),
此外:
DB::table('reviews')->insert($review);
你在循环之外使用它吗?如果是这样,它没有多大意义,因为在每个循环运行中你再次设置它。但是如果你在循环内部进行,你也可以优化它来不运行那么多的插入(显然对于41个记录它没有太大的区别,但是对于成千上万的它会这样做。)