我有两个或将来可能会有更多div与css中的背景图像。我想在一个循环中淡入淡出它们。
我正在尝试做这样的事情,但它不起作用。
$(window).load(function(){
var divs = $('.fade');
function fade() {
var current = $('.current');
var currentIndex = divs.index(current),
nextIndex = currentIndex + 1;
if (nextIndex >= divs.length) {
nextIndex = 0;
}
var next = divs.eq(nextIndex);
next.stop().fadeIn(2000, function() {
$(this).addClass('current');
});
current.stop().fadeOut(2000, function() {
$(this).removeClass('current');
setTimeout(fade, 2500);
});
}
fade();
#one {
background-image: url("Test_bg.jpg");
margin-top: -150px;
min-height: 100%;
background-attachment: fixed;
}
#two {
background-image: url("Test_bg1.jpg");
margin-top: -150px;
min-height: 100%;
display: block;
background-attachment: fixed;
}
<div id="one" class="fade current">
</div>
<div id="two" class="fade">
</div>
感谢您的帮助
答案 0 :(得分:0)
你最后在})
处导致语法错误
$(window).load(function(){
var divs = $('.fade');
function fade() {
var current = $('.current');
var currentIndex = divs.index(current),
nextIndex = currentIndex + 1;
if (nextIndex >= divs.length) {
nextIndex = 0;
}
var next = divs.eq(nextIndex);
next.stop().fadeIn(2000, function() {
$(this).addClass('current');
});
current.stop().fadeOut(2000, function() {
$(this).removeClass('current');
setTimeout(fade, 2500);
});
}
fade();
})
&#13;
#one {
color: red
}
#two {
color: blue
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="one" class="fade current">a
</div>
<div id="two" class="fade">b
</div>
&#13;