Libgdx - 大约2个玩家游戏。我希望每个玩家都可以用一根手指触摸自己的区域

Question

我创造了2个玩家游戏，每个玩家都拥有自己的区域。我希望每个玩家都可以用一根手指触摸自己的区域。所以首先我在“触地”功能中限制为“2指针”。

stopUpdateLocation

但问题是如果一个玩家用他的2个手指触摸他自己的区域，另一个玩家将无法触及他自己的区域。我该如何解决这个问题？谢谢。

Answer 1

你不应该根据指针编号拒绝。

如果你想让屏幕两侧的第一个指针向下，你可以这样做（未经测试）：

private int player1Pointer = -1, player2Pointer = -1;
private int player1X, player1Y, player2X, player2Y;

//...

public boolean touchDown(int screenX, int screenY, int pointer, int button){

    // Assuming top and bottom halves of screen:
    if (screenY > Gdx.graphics.getHeight() / 2){ // player 1 side
        if (player1Pointer >= 0) // player 1 already touching somewhere
            return false;
        player1Pointer = pointer;
        player1X = screenX;
        player1Y = screenY;
    } else { //player 2 side
        if (player2Pointer >= 0) // player 2 already touching somewhere
            return false;
        player2Pointer = pointer;
        player2X = screenX;
        player2Y = screenY;
    }
    return true;
}

public boolean touchDragged (int screenX, int screenY, int pointer) {
    if (pointer == player1Pointer){
        player1X = screenX;
        player1Y = screenY;
        return true;
    }
    if (pointer == player2Pointer){
        player2X = screenX;
        player2Y = screenY;
        return true;
    }
    return false;
}

public boolean touchUp (int screenX, int screenY, int pointer, int button) {
    if (pointer == player1Pointer){
        player1Pointer = -1;
        return true;
    }
    if (pointer == player2Pointer){
        player2Pointer = -1;
        return true;
    }
    return false;
}

Answer 2

你做不到。简单地假设球员公平，只触摸他们自己的区域。根据点击的区域处理点击次数，然后将操作分配给相应的玩家编号。

如果您需要区域内的指针索引，只需根据区域将指针编号分配给播放器1或2.在指针被触摸时删除分配。所以你现在总是在当前时刻将哪个指针编号分配给哪个玩家。

假设指针0是玩家1而指针1是玩家2则不起作用。