Question

我需要根据将数据插入mysql表后的结果在ajax调用中自定义成功消息，

 $.ajax({
             data: dataString,
             type: 'POST',
             url: 'mypage.php',
             success: function(data)
             {
                 if (data === 'success') {
                    alert("New record created successfull");
                 }else{alert("something goes wrong"); }
             }
            });

这是php代码

 <?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDBPDO";

try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john@example.com')";
// use exec() because no results are returned
$conn->exec($sql);
echo "success";
}
catch(PDOException $e)
{
echo "fail";
}

$conn = null;
?>

当我尝试检查从php页面返回的消息时，我通过此ajax调用获得正确的警报

$.ajax({
             data: dataString,
             type: 'POST',
             url: 'mypage.php',
             success: function(data)
             {
                 alert(data);
             }
            });

我尝试了很多东西，但我找不到确切的问题，任何帮助都会受到赞赏。

Answer 1

这将起作用我在另一种情况下使用相同的代码：

if ($.trim(data) === 'success') {
   alert("New record created successfull");
}else{alert("something goes wrong"); }

ajax调用中的succes函数取决于PDO的回显

1 个答案: