如何获取MAX函数的相应列值？

Question

我有以下查询为MAX（date_announced）提供最新的date_announced但是没有给出software_product_build的相应值？ 如何获得MAX的相应software_product_build值（date_announced）？

   select 
   software_product_build,
   MAX(date_announced) as date_announced
    from software_product_builds
   group by software_product_id

一个案例： -

   select software_product_build,
   MAX(date_announced) as date_announced
    from software_product_builds
    where software_product_build LIKE '%QCA6290.LA.0.1%' group by software_product_id;

OUTPUT:-
|------software_product_build------|-------date_announced------|
--QCA6290.LA.0.1-00001-STD.INT-6---|------2017-03-13 21:13:32---


select software_product_build from software_product_builds where date_announced='2017-03-13 21:13:32';

OUTPUT:-
CI_QCA6290.LA.0.1-03091-STD.INT-61

Answer 1

首先，您需要获取每个软件产品ID的最大日期，然后您才能找到该最大日期的软件产品构建。

选择spb.software_product_build，    Tmp.date_announced     来自software_product_builds spb join （选择software_product_id，    MAX（date_announced）为date_announced     来自software_product_builds    group by software_product_id）as tmp on（tmp.software_product_id = spb.software_product_id and tmp.date_announced = spb.date_announced）