我有一个使用另一个带有ngIf语句的组件的组件。我想只在ngIf评估为true时才加载第二个组件。
编辑:找到一篇几乎可以满足我需要的文章: https://medium.com/@matanlurey/lazy-loading-with-angular-dart-14f58004f988。但是,在加载库之后,它将获取组件的整个视图。在我的情况下,我需要将它插入父组件的html中的特定位置。类似的东西:
import '../other/edit_component.dart' deferred as otherEdit;
@Component(
selector: 'edit-component',
template: '<other-component *ngIf="canOther"></other-component>
<button type="button" (click)="go()"></button>',
directives: const [
otherEdit.OtherComponent
]
)
class EditComponent {
@Input()
bool canOther = false;
go() {
otherEdit.loadLibrary();
canOther = true;
}
}
答案 0 :(得分:2)
我认为你不能直接做到。您可以做的是使用Angular2_components中的DynamicComponent并在延迟加载后传递该类型。
答案 1 :(得分:0)
让它成功。使用DynamicComponent作为rkj answer的示例。
// the lib that has the component to be loaded
import 'package:somecomponent.dart' deferred as mycomponent;
class mainComponent {
// <div #holder></div> element that we will append the component
@ViewChild('holder', read: ViewContainerRef)
ViewContainerRef holder;
// this will load the component dynamically
final DynamicComponentLoader _componentLoader;
load() {
// clear the html
holder.clear();
// load the component dynamically
ComponentRef componentRef = await _componentLoader
.loadNextToLocation(componentType, holder);
// set some attributes like you would with [attributes]="somevar"
componentRef.instance
..attribute = somevar;
}
mainComponent(this. _componentLoader){}
}